It is currently 19 Oct 2017, 15:15

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# On the coordinate plane is the point(0,0) closer to the

Author Message
Manager
Joined: 23 May 2007
Posts: 107

Kudos [?]: 25 [0], given: 0

On the coordinate plane is the point(0,0) closer to the [#permalink]

### Show Tags

21 Jun 2007, 21:36
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

On the coordinate plane is the point(0,0) closer to the point (u,v) then to the point (u,v+1)?

1.u+ v2(read as v square)= -1
2.v<0

Kudos [?]: 25 [0], given: 0

VP
Joined: 10 Jun 2007
Posts: 1434

Kudos [?]: 350 [0], given: 0

### Show Tags

21 Jun 2007, 21:53
dreamgmat1 wrote:
On the coordinate plane is the point(0,0) closer to the point (u,v) then to the point (u,v+1)?

1.u+ v2(read as v square)= -1
2.v<0

I got B, what's the OA?

If you look closely at the question, origin of the coordinate plane can only be closer to (u,v) than (u,v+1) when v is positive. So if we find out about the sign of v, we can determine if (u,v+1) is closer or not.

(1) u + v^2 = -1. In this case, we know u is positive, but nothing about v. INSUFFICIENT.

(2) Knowing that v<0 answers the question. In this case, (u,v+1) is actually closer to the origin than (u,v). SUFFICIENT.

Kudos [?]: 350 [0], given: 0

Senior Manager
Joined: 27 Jul 2006
Posts: 294

Kudos [?]: 18 [0], given: 0

### Show Tags

22 Jun 2007, 11:36
We dont need to know a lot to answer this question. first thing is to look at a graph. We kow that it is going to be a straight line, and that a line is the shortest distance between two points.

Now if we look at a graph, and set V to O...and look at a line for any value of x. If 1 is added to Y we see that the line gets longer (becomes the hypotenuse of the triangle formed in the two lines) however if one is taken away from y the opposite is true, so we need to figure out which direction Y is heading, toward the X axis or away from the x axis.

If x heads toward the x axis it will get shorter if it moves away from the x axis it will get longer...

If V is less than -1/2 the line will always get shorter..V>-1/2 the line will get longer.

I Insufficient, it only tells us that X is negative
II turns out to be also insufficient since 0>V>-1/2 is also possible.

together is also insufficient since 0>v>-1. For instance V = -1/2 and U=-5/4

It seems to me that E is in order.

Kudos [?]: 18 [0], given: 0

Manager
Joined: 12 Apr 2007
Posts: 166

Kudos [?]: 12 [0], given: 0

### Show Tags

22 Jun 2007, 12:02
E.

I thought B at first too, but then i realized that v can be between -1/2 and 0. in this case, (u,v) is closer to the origin than (u,v+1) is.

S1+S2 only tells us that u is negative, but we can still have the same situation. if v is very small, ie -10, then (u,v+1) is closer to the origin than (u,v). but just like before, if v is between 0 and -1/2, then (u,v) will be closer than (u,v+1).

nice catch defenestrate.

Kudos [?]: 12 [0], given: 0

Current Student
Joined: 03 Oct 2006
Posts: 84

Kudos [?]: [0], given: 0

### Show Tags

22 Jun 2007, 12:24
Challenge 22, Q11

Statement 1 was incorrectly copied from the Challenge. The correct statement is v + u^2 = -1

OA in white below...

OA is A

Kudos [?]: [0], given: 0

Manager
Joined: 23 May 2007
Posts: 107

Kudos [?]: 25 [0], given: 0

### Show Tags

22 Jun 2007, 12:54
Thanks for the correction hd54321
Yes the OA is A .
hd54321 do you remember all the questions from challenges

Kudos [?]: 25 [0], given: 0

Current Student
Joined: 03 Oct 2006
Posts: 84

Kudos [?]: [0], given: 0

### Show Tags

22 Jun 2007, 14:02
dreamgmat1 wrote:
Thanks for the correction hd54321
Yes the OA is A .
hd54321 do you remember all the questions from challenges

I happen to remember this one very well because it's the only 1.5 point question that I got right out of 3 challenges.

Kudos [?]: [0], given: 0

Senior Manager
Joined: 06 Jul 2004
Posts: 468

Kudos [?]: 136 [0], given: 0

Location: united states

### Show Tags

22 Jun 2007, 16:49
Well, if the (1) statement is changed, the answer should be D. Both equations imply that v is negative and hence (u^2 + v^2) is larger than (u^2 + (v+1)^2) in both cases.
_________________

for every person who doesn't try because he is
afraid of loosing , there is another person who
keeps making mistakes and succeeds..

Kudos [?]: 136 [0], given: 0

22 Jun 2007, 16:49
Display posts from previous: Sort by