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On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1 (B) -1/2 (C) 0 (D) 1/2 (E) 1

Practice Questions Question: 7 Page: 153 Difficulty: 600

On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1 (B) -1/2 (C) 0 (D) 1/2 (E) 1

Since the graph is symmetric with respect to line \(x = 2\), then the value of \(y\) when \(x = 3\) will be the same as the value of \(y\) when \(x = 1\), so 1.

Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y = [#permalink]

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30 Jul 2012, 02:18

(E) 1

its symmetric with respect to x=2. when x=1, 1 unit to the left of x(2), y is 1. when x=3, 1 unit to the right of x(2), y should again be 1 as it is symmetric.

On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1 (B) -1/2 (C) 0 (D) 1/2 (E) 1

Since the graph is symmetric with respect to line \(x = 2\), then the value of \(y\) when \(x = 3\) will be the same as the value of \(y\) when \(x = 1\), so 1.

Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y = [#permalink]

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02 Jan 2013, 07:18

1

This post received KUDOS

Bunuel wrote:

Attachment:

Graph.png

On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1 (B) -1/2 (C) 0 (D) 1/2 (E) 1

Half of the entire graph is a mirror image of the other side. The center coordinate is (2,0) according to the graph. Thus, y when x=1 and y when x-3 are equal.

Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y = [#permalink]

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16 Jul 2014, 02:31

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y = [#permalink]

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09 Sep 2014, 11:12

Bunuel wrote:

Attachment:

Graph.png

On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1 (B) -1/2 (C) 0 (D) 1/2 (E) 1

Practice Questions Question: 7 Page: 153 Difficulty: 600

graph is symmetric with respect to the vertical line

Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y = [#permalink]

Show Tags

21 Sep 2015, 22:33

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1 (B) -1/2 (C) 0 (D) 1/2 (E) 1

We are given that the graph is SYMMETRIC along the vertical line x = 2. We are also given that when x = 1, y = 1. We are asked to determine the value of y when x is 3. Keep in mind that when x = 1, it is ONE UNIT away from the line x = 2, and when x = 3, it is also ONE UNIT away from the line x = 2.

Since the y-coordinate is 1, when x is 1, the y-coordinate is ALSO 1 when x is 3. Again, this is because the graph is symmetric with the line x = 2.

Another way to look at this problem is to see that the point (1,1) is actually being reflected over the line x = 2.

We see that the point (1,1) is exactly 1 unit from the line x = 2. In fact the point (2,1) is on the line x = 2 which is exactly 1 unit from (1,1). However, (1,1) is exactly 1 unit on the LEFT of (2,1), so by symmetry, the point that is exactly 1 unit on the RIGHT of (2,1) is (3,1). Thus the y-coordinate is 1.

Answer E.
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