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On the real number line, there are four points P, Q, S, and [#permalink]

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14 Apr 2011, 04:04

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

82% (02:06) correct
18% (00:57) wrong based on 127 sessions

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On the real number line, there are four points P, Q, S, and T, with coordinates p, q, s, and t, respectively. Suppose p < q < s < t, p = -1, s = 2. If the distance between P and Q is twice the distance between Q and S, and S is the midpoint of Q and T, then T has coordinate

On the real number line, there are four points P, Q, S, and T, with coordinates p, q, s, and t, respectively. Suppose p < q < s < t, p = -1, s = 2. If the distance between P and Q is twice the distance between Q and S, and S is the midpoint of Q and T, then T has coordinate

Re: On the real number line, there are four points P, Q, S, and [#permalink]

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14 Jul 2016, 11:24

gmatpapa wrote:

On the real number line, there are four points P, Q, S, and T, with coordinates p, q, s, and t, respectively. Suppose p < q < s < t, p = -1, s = 2. If the distance between P and Q is twice the distance between Q and S, and S is the midpoint of Q and T, then T has coordinate

No fancy mathematics is need here just make a big line and divide it into 4 parts (like we do in a number line)

Now since the ascending order is p,q,s,t ; name the parts p,q,s and finally t in the same order p=-1 q= unknown, s=2, t= unknown This is the halfway down the question

Then the question tells us P to Q=2 Q to S It means p=-1 q=1,s=2 {p to q= 1-(-1)=2; and since s we know is 2 then q to us is 2-1 =1} S is the average of q and t \(therefore 2=1+\frac{t}{2}\)

t+1 =4 t=3

Answer is D
_________________

Posting an answer without an explanation is "GOD COMPLEX". The world doesn't need any more gods. Please explain you answers properly. FINAL GOODBYE :- 17th SEPTEMBER 2016. .. 16 March 2017 - I am back but for all purposes please consider me semi-retired.

On the real number line, there are four points P, Q, S, and [#permalink]

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14 Jul 2016, 11:26

gmatpapa wrote:

On the real number line, there are four points P, Q, S, and T, with coordinates p, q, s, and t, respectively. Suppose p < q < s < t, p = -1, s = 2. If the distance between P and Q is twice the distance between Q and S, and S is the midpoint of Q and T, then T has coordinate

No fancy mathematics is need here just make a big line and divide it into 4 parts (like we do in a number line)

Now since the ascending order is p,q,s,t ; name the parts p,q,s and finally t in the same order p=-1 q= unknown, s=2, t= unknown This is the halfway down the question

Then the question tells us distance from (P to Q)=twice the distance from (Q to S) It means p=-1 q=1,s=2 {p to q= 1-(-1)=2; and since s we know is 2 then q to us is 2-1 =1} S is the average of q and t therefore \(S=\frac{q+t}{2}\)

therefore \(2=\frac{1+t}{2}\)

t+1 =4 t=3

Answer is D
_________________

Posting an answer without an explanation is "GOD COMPLEX". The world doesn't need any more gods. Please explain you answers properly. FINAL GOODBYE :- 17th SEPTEMBER 2016. .. 16 March 2017 - I am back but for all purposes please consider me semi-retired.

gmatclubot

On the real number line, there are four points P, Q, S, and
[#permalink]
14 Jul 2016, 11:26

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