Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 24 May 2017, 08:11

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# One hour after Matthew started waking from x to y, a distanc

Author Message
TAGS:

### Hide Tags

Manager
Joined: 04 Jan 2013
Posts: 80
Followers: 0

Kudos [?]: 11 [0], given: 1

One hour after Matthew started waking from x to y, a distanc [#permalink]

### Show Tags

08 Jan 2013, 14:45
3
This post was
BOOKMARKED
00:00

Difficulty:

25% (medium)

Question Stats:

78% (02:27) correct 22% (02:16) wrong based on 155 sessions

### HideShow timer Statistics

One hour after Matthew started waking from x to y, a distance of 45km, Johnny started walking along the same road from y to x. Matthew's walking rate was 3 km per hour and Johnny's was 4km per hour, how many km had Johnny walked when they met?

A. 24
B. 23
C. 22
D. 21
E. 19.5
[Reveal] Spoiler: OA

Last edited by Bunuel on 09 Jan 2013, 03:06, edited 1 time in total.
Renamed the topic, edited the question and added OA.
VP
Status: Been a long time guys...
Joined: 03 Feb 2011
Posts: 1381
Location: United States (NY)
Concentration: Finance, Marketing
GPA: 3.75
Followers: 178

Kudos [?]: 1462 [0], given: 62

Re: one hour after matthew started walking from x to y,a distanc [#permalink]

### Show Tags

08 Jan 2013, 19:39
chiccufrazer1 wrote:
One hour after matthew started waking from x to y,a distance of 45km,johnny started walking along the same road from y to x..matthew's walking rate was 3 km per hour and johnny's was 4km per hour,how many km had johnny walked when they met?

A.24
B.23
C.22
D.21
E.19.5

The best method to solve such questions is the summation of distance method.
Please note that when Matthew and Johny would meet, the sum of the distance covered will be the lenth of the journey i.e. 45 km.
Distance covered by Matthew=$$3(t+1)$$
Distance covered by Johny=$$4t$$
where t=time taken by Johny.
Therefore $$3(t+1) + 4t = 45$$
t will come as 6.
Distance covered by Johny is $$4t$$ or $$4*6$$=$$24km$$ Ans.
+1A
_________________
Manager
Joined: 04 Jan 2013
Posts: 80
Followers: 0

Kudos [?]: 11 [0], given: 1

Re: one hour after matthew started walking from x to y,a distanc [#permalink]

### Show Tags

08 Jan 2013, 22:09
wow..u have done in a simple way indeed..i tried using the train's formula which states that (v2+v1)*t=D,but it did not work..would you please explain to me why i had problems using that formula?

Posted from my mobile device
VP
Status: Been a long time guys...
Joined: 03 Feb 2011
Posts: 1381
Location: United States (NY)
Concentration: Finance, Marketing
GPA: 3.75
Followers: 178

Kudos [?]: 1462 [0], given: 62

Re: one hour after matthew started walking from x to y,a distanc [#permalink]

### Show Tags

08 Jan 2013, 22:16
I assume that v1 and v2 are respective speeds.
Here the formula won't work because the two start at different times. Had they started at same time, the formula would have been justified.
I hope you getting my point.
_________________
Moderator
Joined: 02 Jul 2012
Posts: 1223
Location: India
Concentration: Strategy
GMAT 1: 740 Q49 V42
GPA: 3.8
WE: Engineering (Energy and Utilities)
Followers: 124

Kudos [?]: 1483 [4] , given: 116

Re: one hour after matthew started walking from x to y,a distanc [#permalink]

### Show Tags

08 Jan 2013, 23:05
4
KUDOS
1
This post was
BOOKMARKED
chiccufrazer1 wrote:
One hour after matthew started waking from x to y,a distance of 45km,johnny started walking along the same road from y to x..matthew's walking rate was 3 km per hour and johnny's was 4km per hour,how many km had johnny walked when they met?

A.24
B.23
C.22
D.21
E.19.5

Just an alternative method...

After the first hour the distance is 42 km (45-3). Now the problem can be treated as if bothof them started at the same time. Since the speeds are in the ratio 3 : 4, the distances will also be in the same ratio. Splitting 42 in that ratio we get 18 : 24. So answer is 24.

Hence A.
_________________

Did you find this post helpful?... Please let me know through the Kudos button.

Thanks To The Almighty - My GMAT Debrief

GMAT Reading Comprehension: 7 Most Common Passage Types

Manager
Joined: 04 Jan 2013
Posts: 80
Followers: 0

Kudos [?]: 11 [0], given: 1

Re: one hour after matthew started walking from x to y,a distanc [#permalink]

### Show Tags

08 Jan 2013, 23:33
MacFauz wrote:
chiccufrazer1 wrote:
One hour after matthew started waking from x to y,a distance of 45km,johnny started walking along the same road from y to x..matthew's walking rate was 3 km per hour and johnny's was 4km per hour,how many km had johnny walked when they met?

A.24
B.23
C.22
D.21
E.19.5

Just an alternative method...

After the first hour the distance is 42 km (45-3). Now the problem can be treated as if bothof them started at the same time. Since the speeds are in the ratio 3 : 4, the distances will also be in the same ratio. Splitting 42 in that ratio we get 18 : 24. So answer is 24.

Hence A.

what would happen if the were walking in the same direction?

Posted from my mobile device
Moderator
Joined: 02 Jul 2012
Posts: 1223
Location: India
Concentration: Strategy
GMAT 1: 740 Q49 V42
GPA: 3.8
WE: Engineering (Energy and Utilities)
Followers: 124

Kudos [?]: 1483 [0], given: 116

Re: one hour after matthew started walking from x to y,a distanc [#permalink]

### Show Tags

09 Jan 2013, 02:12
chiccufrazer1 wrote:
MacFauz wrote:
chiccufrazer1 wrote:
One hour after matthew started waking from x to y,a distance of 45km,johnny started walking along the same road from y to x..matthew's walking rate was 3 km per hour and johnny's was 4km per hour,how many km had johnny walked when they met?

A.24
B.23
C.22
D.21
E.19.5

Just an alternative method...

After the first hour the distance is 42 km (45-3). Now the problem can be treated as if bothof them started at the same time. Since the speeds are in the ratio 3 : 4, the distances will also be in the same ratio. Splitting 42 in that ratio we get 18 : 24. So answer is 24.

Hence A.

what would happen if the were walking in the same direction?

Posted from my mobile device

In such a case, the total distance would be irrelevant.

In the 1st hour Mathew would have travelled 3 kms.
Let us say that after this first hour it takes Matthew and Johnny "t" hours to meet.
So, distance travelled by Matthew and distance travelled by Johnny should be the same.

Distance travelled by Matthew = 3 + 3*t
Distance travelled by Johnny = 4*t

3 + 3*t = 4*t. So, t = 3 hrs. So distance travelled would be = 4*3 = 12 kms
_________________

Did you find this post helpful?... Please let me know through the Kudos button.

Thanks To The Almighty - My GMAT Debrief

GMAT Reading Comprehension: 7 Most Common Passage Types

Manager
Joined: 25 Jun 2012
Posts: 71
Location: India
WE: General Management (Energy and Utilities)
Followers: 4

Kudos [?]: 119 [0], given: 16

Re: one hour after matthew started walking from x to y,a distanc [#permalink]

### Show Tags

09 Jan 2013, 02:55
I used the train formula but modified the distance travelled.

After one hour, mathew has travelled 3 kms so 42 kms left when Johnny starts.

so distance to travel is 42 kms for both, in bwtween which they will meet,

No d = 42 kms
t = hrs
speed = 3+4 (since they moving in opposite direction to each other) = 7

s = d/t
7 = 42/t
t = 6 hrs

So distance travelled by John = 4*6 = 24 kms

Option A
Intern
Joined: 23 Nov 2012
Posts: 35
Location: France
Concentration: Finance, Economics
Schools: Said (D)
GMAT 1: 710 Q49 V38
WE: Sales (Investment Banking)
Followers: 0

Kudos [?]: 14 [0], given: 19

Re: One hour after Matthew started waking from x to y, a distanc [#permalink]

### Show Tags

09 Jan 2013, 05:07
1
This post was
BOOKMARKED
Quote:
One hour after Matthew started waking from x to y, a distance of 45km, Johnny started walking along the same road from y to x. Matthew's walking rate was 3 km per hour and Johnny's was 4km per hour, how many km had Johnny walked when they met?

Since M started walking one hour before J the distance they have to travel together has to be 45km-3km/h*1h=42km

The combinded speed of M and J is 3km/h+4km/h=7km/h. They thus need 42km/7(km/h)=6h to cover the 42km between them. Therefore J has to walk 4km/h*6h=24km
_________________

Hodor?

Kudo!

Manager
Joined: 18 Oct 2011
Posts: 90
Location: United States
Concentration: Entrepreneurship, Marketing
GMAT Date: 01-30-2013
GPA: 3.3
Followers: 2

Kudos [?]: 74 [0], given: 0

Re: One hour after Matthew started waking from x to y, a distanc [#permalink]

### Show Tags

09 Jan 2013, 09:15
If Matthew has an hour heads start then that means the distance between them when Johnny starts walking is 42kms. Each hr their combined distance travelled is 7 kms (3km/hr + 4km/hr). That must mean that it will take 6 hours for them to meet each other.

In 6 hrs Johnny walked 6x4 = 24 kms.
Manager
Joined: 04 Jan 2013
Posts: 80
Followers: 0

Kudos [?]: 11 [0], given: 1

Re: one hour after matthew started walking from x to y,a distanc [#permalink]

### Show Tags

10 Jan 2013, 02:21
bhavinshah5685 wrote:
I used the train formula but modified the distance travelled.

After one hour, mathew has travelled 3 kms so 42 kms left when Johnny starts.

so distance to travel is 42 kms for both, in bwtween which they will meet,

No d = 42 kms
t = hrs
speed = 3+4 (since they moving in opposite direction to each other) = 7

s = d/t
7 = 42/t
t = 6 hrs

So distance travelled by John = 4*6 = 24 kms

Option A

can we approach this problem in the same way(willard types at an average speed of 40 words per minute and george types at 60 words per minute.if willard begins typing a manuscript at 4:20 and george begins typing an identical copy of the manuscript at 5:00,at what time will they be typing the same word?
A.5:10 B.5:30 C.5:40 D.6:00 E.6:20''

Posted from my mobile device
Intern
Joined: 11 Feb 2013
Posts: 19
Followers: 0

Kudos [?]: 6 [0], given: 4

Re: One hour after Matthew started waking from x to y, a distanc [#permalink]

### Show Tags

19 Mar 2013, 06:43
speed of mathew = 3 kph
let time be 't'
tot dist travelled by mathew = 3t

johny starts an hour later ...so john's time would be = t-1
speed of johny = 4 kph
tot dist travelled bby johny = 4(t-1)

since tot dist given is 45 kms so...
3t + 4(t-1) = 45
7t - 4 = 45
7t = 41
t= 41/7 hrs

so tot dist travelled by johny is = 4(t-1)
= 4 ( 41/7 - 1)
= 4 ( 34/7)
= 136/7
= 19.42 = 19.5 (approx0

if its wrong...please explain me the reason...
Math Expert
Joined: 02 Sep 2009
Posts: 38856
Followers: 7723

Kudos [?]: 105991 [0], given: 11602

Re: One hour after Matthew started waking from x to y, a distanc [#permalink]

### Show Tags

20 Mar 2013, 04:47
Perhaps wrote:
One hour after Matthew started waking from x to y, a distance of 45km, Johnny started walking along the same road from y to x. Matthew's walking rate was 3 km per hour and Johnny's was 4km per hour, how many km had Johnny walked when they met?

A. 24
B. 23
C. 22
D. 21
E. 19.5

speed of mathew = 3 kph
let time be 't'
tot dist travelled by mathew = 3t

johny starts an hour later ...so john's time would be = t-1
speed of johny = 4 kph
tot dist travelled bby johny = 4(t-1)

since tot dist given is 45 kms so...
3t + 4(t-1) = 45
7t - 4 = 45
7t = 41
t= 41/7 hrs

so tot dist travelled by johny is = 4(t-1)
= 4 ( 41/7 - 1)
= 4 ( 34/7)
= 136/7
= 19.42 = 19.5 (approx0

if its wrong...please explain me the reason...

The red part above is not correct: 7t - 4 = 45 --> 7t = 49 --> t = 7 --> 4(t - 1) = 24.

Hope it helps.
_________________
Intern
Joined: 11 Feb 2013
Posts: 19
Followers: 0

Kudos [?]: 6 [0], given: 4

Re: One hour after Matthew started waking from x to y, a distanc [#permalink]

### Show Tags

20 Mar 2013, 06:08
oops...
thanks bunuel
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 15420
Followers: 649

Kudos [?]: 206 [0], given: 0

Re: One hour after Matthew started waking from x to y, a distanc [#permalink]

### Show Tags

17 Mar 2017, 23:54
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Intern
Joined: 03 Jan 2016
Posts: 43
Location: India
WE: Engineering (Energy and Utilities)
Followers: 0

Kudos [?]: 1 [0], given: 13

Re: One hour after Matthew started waking from x to y, a distanc [#permalink]

### Show Tags

18 Mar 2017, 19:52
So the distance left between jho & Mat is 42 km.
Relative Speed = 3 + 4 = 7 km as both are moving towards each other.
So Both will meet after 42/7 = 6 hours.
So Math travels = 4 * 6 =24 Km

Regards
G V V S Narayana raju
Re: One hour after Matthew started waking from x to y, a distanc   [#permalink] 18 Mar 2017, 19:52
Similar topics Replies Last post
Similar
Topics:
2 Scott starts jogging from Point X to Point Y. A half hour later his fr 2 19 May 2016, 05:18
A man walks from B to C, a distance of x miles, at 8 miles per hour an 4 27 Mar 2016, 13:29
1 One hour before John started walking from P to Q, a distance 7 10 Sep 2015, 20:44
18 Half an hour after Car A started traveling from Newtown to 8 12 Nov 2016, 19:58
11 One hour after Adrienne started walking the 60 miles from X 11 03 Oct 2016, 10:10
Display posts from previous: Sort by