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Over a six-game stretch of her basketball season, Sonya scored 50, 47,

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Joined: 02 Sep 2009
Posts: 61396
Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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06 Mar 2017, 00:55
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5% (low)

Question Stats:

89% (01:16) correct 11% (01:40) wrong based on 72 sessions

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Over a six-game stretch of her basketball season, Sonya scored 50, 47, 40, 43, 55, and x points. If her average score was x, what is the value of x?

A. 45
B. 46
C. 47
D. 48
E. 49

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Posts: 309
Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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06 Mar 2017, 01:22
Average of 6 games = (50+47+40+43+55+x)/6 = x

50+47+40+43+55+x = 6x

Solving for x gives x=47

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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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10 Mar 2017, 09:27
Bunuel wrote:
Over a six-game stretch of her basketball season, Sonya scored 50, 47, 40, 43, 55, and x points. If her average score was x, what is the value of x?

A. 45
B. 46
C. 47
D. 48
E. 49

We can set up the following equation to determine x:

x = (50 + 47 + 40 + 43 + 55 + x)/6

6x = 235 + x

5x = 235

x = 47

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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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10 Mar 2017, 22:26
we can calculate x without much of calculation through standard deviation as we know -ve deviation =+deviation(taken form mean).
so when we take deviation form 47(taking x=47) then -7(+)-4=8+3 that will equal to zero so the value for X will be 47

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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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10 Mar 2017, 23:57
Bunuel wrote:
Over a six-game stretch of her basketball season, Sonya scored 50, 47, 40, 43, 55, and x points. If her average score was x, what is the value of x?

A. 45
B. 46
C. 47
D. 48
E. 49

$$\frac{( 50 + 47 + 43 + 55 + x )}{6} = x$$

Or, $$235+ x = 6x$$

Or, $$5x = 235$$

So, $$x = 47$$

Thus, answer must be (C) 47
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Joined: 11 Sep 2015
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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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03 Dec 2019, 14:45
Top Contributor
Bunuel wrote:
Over a six-game stretch of her basketball season, Sonya scored 50, 47, 40, 43, 55, and x points. If her average score was x, what is the value of x?

A. 45
B. 46
C. 47
D. 48
E. 49

Sonya scored 50, 47, 40, 43, 55, and x points. Her average score was x
We can write: (50 + 47 + 40 + 43 + 55 + x)/6 = x
Multiply both sides by 6 to get: 50 + 47 + 40 + 43 + 55 + x = 6x
Simplify to get: 235 + x = 6x
Subtract x from both sides: 235 = 5x
Solve: x = 235/5 = 47

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Brent
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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,   [#permalink] 03 Dec 2019, 14:45
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