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Over a six-game stretch of her basketball season, Sonya scored 50, 47,

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Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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New post 06 Mar 2017, 01:55
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

90% (01:17) correct 10% (01:50) wrong based on 68 sessions

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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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New post 06 Mar 2017, 02:22
Average of 6 games = (50+47+40+43+55+x)/6 = x

50+47+40+43+55+x = 6x

Solving for x gives x=47

Answer is C
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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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New post 10 Mar 2017, 10:27
Bunuel wrote:
Over a six-game stretch of her basketball season, Sonya scored 50, 47, 40, 43, 55, and x points. If her average score was x, what is the value of x?

A. 45
B. 46
C. 47
D. 48
E. 49


We can set up the following equation to determine x:

x = (50 + 47 + 40 + 43 + 55 + x)/6

6x = 235 + x

5x = 235

x = 47

Answer: C
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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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New post 10 Mar 2017, 23:26
we can calculate x without much of calculation through standard deviation as we know -ve deviation =+deviation(taken form mean).
so when we take deviation form 47(taking x=47) then -7(+)-4=8+3 that will equal to zero so the value for X will be 47

hence answer must be C
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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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New post 11 Mar 2017, 00:57
Bunuel wrote:
Over a six-game stretch of her basketball season, Sonya scored 50, 47, 40, 43, 55, and x points. If her average score was x, what is the value of x?

A. 45
B. 46
C. 47
D. 48
E. 49


\(\frac{( 50 + 47 + 43 + 55 + x )}{6} = x\)

Or, \(235+ x = 6x\)

Or, \(5x = 235\)

So, \(x = 47\)

Thus, answer must be (C) 47
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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,  [#permalink]

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New post 03 Dec 2019, 15:45
Top Contributor
Bunuel wrote:
Over a six-game stretch of her basketball season, Sonya scored 50, 47, 40, 43, 55, and x points. If her average score was x, what is the value of x?

A. 45
B. 46
C. 47
D. 48
E. 49


Sonya scored 50, 47, 40, 43, 55, and x points. Her average score was x
We can write: (50 + 47 + 40 + 43 + 55 + x)/6 = x
Multiply both sides by 6 to get: 50 + 47 + 40 + 43 + 55 + x = 6x
Simplify to get: 235 + x = 6x
Subtract x from both sides: 235 = 5x
Solve: x = 235/5 = 47

Answer: C

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Brent
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Re: Over a six-game stretch of her basketball season, Sonya scored 50, 47,   [#permalink] 03 Dec 2019, 15:45
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