Bunuel wrote:
P and Q are each circular regions. What is the radius of Q, if the area of P minus the area of Q is 15π and P has a circumference that is 4 times that of Q?
Let the radius of Circular region P be p and that of Q be q
Given:
\(2\pi*p=4*2\pi*q\)
this implies, \(p=4q\).................a
Also, \(\pi*p^2-\pi*q^2=15\pi\)
therefore, \(p^2-q^2=15\)
Using a, we get
\(16q^2-q^2=15\)
\(15q^2=15\)
therefore, \(q^2=1\)or \(q=1\)
Answer: B
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~R.
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