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P&C question

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Senior Manager
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P&C question [#permalink]

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New post 19 Jun 2008, 04:56
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Can u please tell me how to solve this

Many thanks
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The world is continuous, but the mind is discrete

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Senior Manager
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Re: P&C question [#permalink]

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New post 19 Jun 2008, 06:18
Hmm, looks like quite easy.

For each digit, we have 26 letters + 10 numbers = 36 possibilities. There are 7 digits. So, total number of codes is 36*36*36*36*36*36*36 = 36^7.

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Re: P&C question [#permalink]

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New post 19 Jun 2008, 06:23
greenoak..that was awesome..

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Re: P&C question [#permalink]

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New post 19 Jun 2008, 06:39
I think that was an irony. But don't laugh at me.
I usually make mistakes in such questions :? In fact every time I see a probability/combinations problems, I'm dead. :(

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Re: P&C question [#permalink]

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New post 19 Jun 2008, 06:42
36 ^7 for me too....any other answers?

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Re: P&C question [#permalink]

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New post 19 Jun 2008, 06:45
I get E, \(36^7\) too, but i'm kind of surprised the answer wasn't \(6^{14}\) since 36 is a perfect square of 6.

I guess that depends on \(36^7\) being the correct answer.

gmat2ndtime wrote:
36 ^7 for me too....any other answers?

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Kudos [?]: 615 [0], given: 32

Senior Manager
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Kudos [?]: 69 [0], given: 0

Re: P&C question [#permalink]

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New post 19 Jun 2008, 23:20
Guys the OA for this one is 36^7

any ideas on what basic material i can cover up so that i polish my P&C and Probability skills
Do the manhattan books help.

Many thanks
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The world is continuous, but the mind is discrete

Kudos [?]: 69 [0], given: 0

Re: P&C question   [#permalink] 19 Jun 2008, 23:20
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