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# P = p1 p2 p3 is a product of three distinct primes.

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Manager
Joined: 14 May 2005
Posts: 85

Kudos [?]: 29 [0], given: 0

Location: San Francisco
P = p1 p2 p3 is a product of three distinct primes. [#permalink]

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22 Oct 2006, 19:37
00:00

Difficulty:

(N/A)

Question Stats:

50% (00:05) correct 50% (00:00) wrong based on 3 sessions

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P = p1 p2 p3 is a product of three distinct primes. Determine P:

(S1) 39 is a divisor of P
(S2) 15 is a divisor of P

Kudos [?]: 29 [0], given: 0

Senior Manager
Joined: 14 Aug 2006
Posts: 361

Kudos [?]: 53 [0], given: 0

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22 Oct 2006, 19:41
C

1) from 1 we know the number is 3* 13 but the other prime can be 2, 5, 7, 11 etc.. SO INSUFF

2) from 2 we know the number is 3 * 5 the other prime can be 2, 7, 11 etc

Combined the number has to be 3* 5* 13

Kudos [?]: 53 [0], given: 0

Senior Manager
Joined: 08 Jun 2006
Posts: 335

Kudos [?]: 64 [0], given: 0

Location: Washington DC

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22 Oct 2006, 19:47
C

From 1 â€“ insufficient
P = P1 * P2 * P3 = 39 * k (k is an integer) = 3 * 13 * k
Two prime numbers are 3, 13. we donâ€™t know the 3rd one

From 2 â€“ insufficient
P = P1 * P2 * P3 = 15 * m (m is an integer) = 3 * 5 * k
Consider P1 = 3 and P3 = 5
Two prime numbers are 3, 5. we donâ€™t know the 3rd one

Together
3 prime numbers are 3, 13, 5
P = 3* 13*5

Kudos [?]: 64 [0], given: 0

Retired Moderator
Joined: 05 Jul 2006
Posts: 1748

Kudos [?]: 447 [0], given: 49

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23 Oct 2006, 10:31
P = p1 p2 p3 is a product of three distinct primes. Determine P:

(S1) 39 is a divisor of P
(S2) 15 is a divisor of P

FROM ONE

P = P1*P2*P3 = 3*13*P3........NOT SUFF

FROM TWO

P =P1*P2*P3 = 3*5*P2.....NOT SUFF

BOTH TOGETHER

P = 5*3*13....SUFF

Kudos [?]: 447 [0], given: 49

Manager
Joined: 14 May 2005
Posts: 85

Kudos [?]: 29 [0], given: 0

Location: San Francisco

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12 Nov 2006, 13:27
Thank you fellas. The OA is C.

Kudos [?]: 29 [0], given: 0

12 Nov 2006, 13:27
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