Last visit was: 24 Apr 2024, 03:35 It is currently 24 Apr 2024, 03:35

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Manager
Manager
Joined: 13 May 2010
Posts: 70
Own Kudos [?]: 160 [0]
Given Kudos: 4
Send PM
Alum
Joined: 19 Mar 2012
Posts: 4341
Own Kudos [?]: 51447 [0]
Given Kudos: 2326
Location: United States (WA)
Concentration: Leadership, General Management
Schools: Ross '20 (M)
GMAT 1: 760 Q50 V42
GMAT 2: 740 Q49 V42 (Online)
GMAT 3: 760 Q50 V42 (Online)
GPA: 3.8
WE:Marketing (Non-Profit and Government)
Send PM
User avatar
Manager
Manager
Joined: 13 May 2010
Posts: 70
Own Kudos [?]: 160 [0]
Given Kudos: 4
Send PM
Alum
Joined: 19 Mar 2012
Posts: 4341
Own Kudos [?]: 51447 [0]
Given Kudos: 2326
Location: United States (WA)
Concentration: Leadership, General Management
Schools: Ross '20 (M)
GMAT 1: 760 Q50 V42
GMAT 2: 740 Q49 V42 (Online)
GMAT 3: 760 Q50 V42 (Online)
GPA: 3.8
WE:Marketing (Non-Profit and Government)
Send PM
Re: M15 Q11 [#permalink]
Expert Reply
consider x=2 and y=4
in this case |x+y| i.e 6>|x-y| i.e 2
Again consider x=2 and y=-4
in this case |x+y| ie 2 < |x-y| i.e 6
hope this helps.
Alum
Joined: 19 Mar 2012
Posts: 4341
Own Kudos [?]: 51447 [0]
Given Kudos: 2326
Location: United States (WA)
Concentration: Leadership, General Management
Schools: Ross '20 (M)
GMAT 1: 760 Q50 V42
GMAT 2: 740 Q49 V42 (Online)
GMAT 3: 760 Q50 V42 (Online)
GPA: 3.8
WE:Marketing (Non-Profit and Government)
Send PM
Re: M15 Q11 [#permalink]
Expert Reply
in general if you want to plug in numbers in questions like these, you need to consider positive, negative and fractional values of all the variables to eleminate/consider one option
Cheers
avatar
Intern
Intern
Joined: 24 Feb 2010
Posts: 7
Own Kudos [?]: 19 [0]
Given Kudos: 0
Send PM
Re: M15 Q11 [#permalink]
For statement 2, use these values to prove that the statement alone is insufficient.

x=2 and y=0
x=3 and y=1
x=-1 and y=-3

Always make a point to check for the inequality with 0 as a value.

Kind Regards,
Ravender
Alum
Joined: 19 Mar 2012
Posts: 4341
Own Kudos [?]: 51447 [0]
Given Kudos: 2326
Location: United States (WA)
Concentration: Leadership, General Management
Schools: Ross '20 (M)
GMAT 1: 760 Q50 V42
GMAT 2: 740 Q49 V42 (Online)
GMAT 3: 760 Q50 V42 (Online)
GPA: 3.8
WE:Marketing (Non-Profit and Government)
Send PM
Re: M15 Q11 [#permalink]
Expert Reply
palsays wrote:
For statement 2, use these values to prove that the statement alone is insufficient.

x=2 and y=0
x=3 and y=1
x=-1 and y=-3

Always make a point to check for the inequality with 0 as a value.

Kind Regards,
Ravender


@palsays
I dont think your values provide insufficiency
for x=2, y=0 |x+y|>|x-y|
for x=3, y=1 |x+y|>|x-y|
for x=-1, y=-3 |x+y|>|x-y|

You have to make one variable negative and one variable postive to show that |x+y|<|x-y|
Cheers
User avatar
Director
Director
Joined: 22 Mar 2011
Posts: 520
Own Kudos [?]: 2136 [0]
Given Kudos: 43
WE:Science (Education)
Send PM
Re: M15 Q11 [#permalink]
teal wrote:
Is \(|x - y| \gt |x + y|\) ?

\(x^2 - y^2 = 9\)
\(x - y = 2\)

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
EACH statement ALONE is sufficient
Statements (1) and (2) TOGETHER are NOT sufficient

Statement (1) by itself is insufficient. S1 gives us information about \((x - y)(x + y)\) but does not tell how \((x - y)\) and \((x + y)\) compare to each other.

Statement (2) by itself is insufficient. S2 gives no information about \((x + y)\) .

Statements (1) and (2) combined are sufficient. From S1 and S2 it follows that \(2(x + y) = 9\) from where \((x + y) = 4.5\) . Now we can state that \(|x - y| = 2 \lt |x + y| = 4.5\) .
The correct answer is C.

I can't get the right numbers to test statement 2 to prove it Insuff. Please help. All the numbers I tried have me NO. Please help.


In fact, the given inequality can be rewritten as \((x-y)^2>(x+y)^2\) - we can square both sides, as they are both positive. Rearranging the terms, the question becomes \(xy<0\) (is the product xy negative)?

Then, it is much easier to understand that neither (1), nor (2) alone is sufficient.
Taking both statements, one can explicitly find the values of x and y (although not necessary), and check whether their product is negative.
That's why the correct answer should be C.
Alum
Joined: 19 Mar 2012
Posts: 4341
Own Kudos [?]: 51447 [0]
Given Kudos: 2326
Location: United States (WA)
Concentration: Leadership, General Management
Schools: Ross '20 (M)
GMAT 1: 760 Q50 V42
GMAT 2: 740 Q49 V42 (Online)
GMAT 3: 760 Q50 V42 (Online)
GPA: 3.8
WE:Marketing (Non-Profit and Government)
Send PM
Re: M15 Q11 [#permalink]
Expert Reply
yeah true that. Precisely my point.

Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests for the latest questions.
Still interested? Check out the "Best Topics" block above for better discussion and related questions.
Thank you for understanding, and happy exploring!
GMAT Club Bot
Re: M15 Q11 [#permalink]
Moderator:
Math Expert
92901 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne