Marcab wrote:
Sammy has x flavors of candies with which to make goody bags for Franks birthday party. Sammy tosses out y flavors, because he doesnt like them. How many different 10-flavor bags can Sammy make from the remaining flavors? (It doesnt matter how many candies are in a bag, only how many flavors).
(1) If Sammy had thrown away 2 additional flavors of candy, he could have made exactly 3,003 different 10-flavor bags.
(2) x = y + 17
We need to determine the number of different 10-flavor goody bags Sammy can make for Frank. Since there were x flavors to begin with and y were thrown away, there are (x - y) remaining flavors. Moreover, since the order in which the flavors are chosen is not important, this is a combination problem. In other words, we must determine whether we have enough information to calculate (x - y)C10.
Statement One Alone:
If Sammy had thrown away 2 additional flavors of candy, he could have made exactly 3,003 different 10-flavor bags.
This statement tells us that (x - y b- 2)C10 = 3003. The important thing to remember when approaching questions like this is that we don’t actually need to find the answer; we simply need to determine whether we have enough information to answer the question. In this case, since there is a unique value for (x - y - 2) that satisfies (x - y - 2)C10 = (x - y - 2)!/((x - y - 12)! * 10!), we can determine (x - y - 2), and thus we can determine x - y. After x - y is determined, it is easy to calculate (x - y)C10.
Statement one alone provides enough information to answer the question.
Statement Two Alone:
x = y + 17
We have x - y = 17; thus, 17C10 = 17!/(7! * 10!) can be calculated.
Statement two alone provides enough information to answer the question.
Answer: D
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