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Re: if yz not equal to zero is 0 < y < 1? [#permalink]
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harikris wrote:

if yz not equal to zero is 0 < y < 1?

1)y < 1/y

2) y=z^2


Statement 1 is true for values between 0 and 1, but is also true for any negative number less than -1 (you can plug in, say, -2 to confirm). So Statement 1 is not sufficient. Statement 2 is clearly not sufficient since we have no information about z besides the fact that it's nonzero.

Taking the Statements together, from Statement 2, y must be positive, since it is equal to a nonzero square. So looking at Statement 1, we can multiply both sides by y, since y is positive, without worrying about whether to reverse the inequality. We then find that y^2 < 1, and if y is positive, that means 0 < y < 1. So the two statements together are sufficient and the answer is C.
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Re: If yz not equal to zero is 0 < y < 1? [#permalink]
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harikris wrote:
If yz not equal to zero is 0 < y < 1?

(1) y < 1/y

(2) y = z^2


Given : If yz not equal to zero

Question : Is 0 < y < 1?

Statement 1: y < 1/y

Case 1: y = 1/2 i.e. Answer to the question is YES
Case 1: y = -2 i.e. Answer to the question is NO
NOT SUFFICIENT

Statement 2: y = z^2

i.e. y is positive as the square of any NON-Zero number z will always be positive but the range of values of y is still unknown hence
NOT SUFFICIENT

Combining the two statements
y is positive and y < 1/y
i.e. y^2 < 1
i.e. 0 < y < 1
SUFFICIENT

Answer: Option C
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Re: If yz not equal to zero is 0 < y < 1? [#permalink]
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Re: If yz not equal to zero is 0 < y < 1? [#permalink]
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