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Re: Division [#permalink]
Question is which "must be true"

So Ans is C (K cannot be prime, as primes cannot be divisible by 6 with remainder as 2)
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Re: Division [#permalink]
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sdas wrote:
Question is which "must be true"

So Ans is C (K cannot be prime, as primes cannot be divisible by 6 with remainder as 2)


That's not correct.

If positive integer k is divided by 6, the quotient is m and the remainder is 2, then which of the following must be true?

I. k + m is even
II. k cannot be a prime number
III. k is divisible by 4


A. None
B. I
C. II
D. III
E. I and II only

Positive integer k is divided by 6, the quotient is m and the remainder is 2 can be expressed as \(k=6m+2\):

If \(m=0\), then \(k=2=prime\) --> discard II and III.
If \(m=1\), then \(k=8\) --> \(k+m=9=odd\) --> discard I.

Answer: A.

Hope it's clear.
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Re: If positive integer k is divided by 6, the quotient is m and [#permalink]
Thanks Bunuel to rectify my careless approach. Of course 2 is prime...
+1 to you
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If positive integer k is divided by 6, the quotient is m and [#permalink]
Economist wrote:
If positive integer k is divided by 6, the quotient is m and the remainder is 2, then which of the following must be true?

I. k + m is even

II. k cannot be a prime number

III. k is divisible by 4

A. None
B. I
C. II
D. III
E. I and II only


I. not true:
let k=8
8=6*1+2
8+1=9 (odd)
II. & III. not true:
let k=2
2=6*0+2
2 is prime and not divisible by 4
A
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Re: If positive integer k is divided by 6, the quotient is m and [#permalink]
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Re: If positive integer k is divided by 6, the quotient is m and [#permalink]
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