If x is a positive integer, is x^(1/2) greater than 20?

x can't be 0
1 - divisible by 30, x can be 30 - in this case, sqrt 30 is not greater than 20, if x = 900 = yes, is greater. NS
2 - divisible by 50, x can be 50 -> in this case, sqrt 50 is 5 sqrt 2 - not greater than 20. if x = 2500 - yes, is greater. NS
1+2 -> x can be 150, sqrt of 150 can be 5 sqrt 6 -> not greater than 20. x can be 1500 - and sqrt of 1500 is greater than 20. both are insufficient. E.

Sqrt(X)>20
Squaring on both sides X>400

i)factors of 30=2x3x5
30,300,420 are also divisible by 30 So we dont have single value.So not sufficient

ii)factors of 50=2x5x5
50,240,500 are also divisible by 50 and So we dont have single value.So not sufficient

Combining i) & ii)

common factors = 2x3x5x5 =150
150,450 is also divisible by 150.we dont have single value.So not sufficient.

therefore the answer is E

mate, there are some serious flaws in your way of thinking.
first of all, when analyzing statement 2, do not, do not, do not use any information from statement 1.
second, as you have pointed out, 150 is <400. This is a Yes/No DS type of question. IF you can clearly say Yes or No, then the information is sufficient. From your msg, you say that 150 is less than 400, that's why it is not sufficient. That's not true.
third, 50 is not divisible by 30, since the prime factorization is different. 30 has 3 distinct factors 2, 3, and 5, while 50 has only 2 distinct factors: 2 and 5.

Thanks Mvictor for pointing out the typo and logical flaws.Hope it si correct now.

I have edited my post

orig condition is x>400?

1. x divisibly by 30, i.e. x=30,600etc..
not suff
2. x divisible by 50 i.e. x =50,500 etc.
not suff
combining both, x= 150, 1500 etc..
so not suff.
ANS :E

Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

If x is a positive integer, is x √ greater than 20?

(1) x is divisible by 30
(2) x is divisible by 50

If we modify the original condition by squaring both sides, we get x>20^2 or x>400. There is one variable (x) and 2 equations are given from the conditions, so there is high chance (D) will be our answer.

From condition 1, the answer is 'no' for x=30 but 'yes' for 1500. This is insufficient.
For condition 2, the answer is 'no' for x=50 but 'yes' for 1500. This is insufficient.
Looking at the conditions together, the answer is 'no' for x=150 but 'yes' for 1500. So the answer becomes (E).

For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.

lcm of 50 and
30 is 150

it can be 150 ,300
,450 ,600


150^ is close to 13

600^ is greater than 20 .. so not sufficient

Answer is E

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