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If v = (w)^2(y)(z), how many positive factors does v have?

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Bunuel
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If v = (w)^2(y)(z), how many positive factors does v have? [#permalink] New post  07 Mar 2016, 09:00
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If v = (w)^2(y)(z), how many positive factors does v have?

(1) w, y and z are integers greater than 1
(2) w, y and z are distinct prime numbers
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nipunjain14
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Re: If v = (w)^2(y)(z), how many positive factors does v have? [#permalink] New post  07 Mar 2016, 22:52
St 1 insufficient
St2: w y and z are prime so number of factors is ;
(2+1)(1+1)(1+1) = 12
Sufficient

Ans: B
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Re: If v = (w)^2(y)(z), how many positive factors does v have? [#permalink] New post  09 Mar 2016, 21:29
Here B is clearly sufficient as we know we really dont have to know the prime factors actually => knowing there powers is enough to get the fators
Hence B
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Re: If v = (w)^2(y)(z), how many positive factors does v have? [#permalink] New post  10 Mar 2016, 02:14
Expert Reply
Bunuel wrote:
If v = (w)^2(y)(z), how many positive factors does v have?

(1) w, y and z are integers greater than 1
(2) w, y and z are distinct prime numbers


Given: v = (w)^2(y)(z)
Required: Number of positive factors of v

We can find the number of factors of N = (x^a)*(y^b)*(z^c) if x, y and z are different prime numbers.
Number of factors = (a+1)(b+ 1)(c+1)

Statement 1: w, y and z are integers greater than 1
If w,y and z are prime, we can find the number of factors. If they are not, we cannot find.
INSUFFICIENT

Statement 2: w, y and z are distinct prime numbers
This clearly tells us that w,y and z are distinct prime numbers.
Hence we can find the number of factors.
Number of factors = 3*2*2 = 12 (Not needed to calculate for the question)
SUFFICIENT

Option B
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akgulhane
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If v = (w)^2(y)(z), how many positive factors does v have? [#permalink] New post  23 Mar 2018, 00:44
TeamGMATIFY wrote:
Bunuel wrote:
If v = (w)^2(y)(z), how many positive factors does v have?

(1) w, y and z are integers greater than 1
(2) w, y and z are distinct prime numbers


Given: v = (w)^2(y)(z)
Required: Number of positive factors of v

We can find the number of factors of N = (x^a)*(y^b)*(z^c) if x, y and z are different prime numbers.
Number of factors = (a+1)(b+ 1)(c+1)

Statement 1: w, y and z are integers greater than 1
If w,y and z are prime, we can find the number of factors. If they are not, we cannot find.
INSUFFICIENT

Statement 2: w, y and z are distinct prime numbers
This clearly tells us that w,y and z are distinct prime numbers.
Hence we can find the number of factors.
Number of factors = 3*2*2 = 12 (Not needed to calculate for the question)
SUFFICIENT

Option B




What if W is negative?
Statement 2 doesnot bound for any of the prime factors to be negative?
If they would have asked for the factors the above explanation is fine.
but they have specifically asked for positive and then both the possibilities must be considered.
Experts please help!!
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amanvermagmat
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Re: If v = (w)^2(y)(z), how many positive factors does v have? [#permalink] New post  23 Mar 2018, 05:00
akgulhane wrote:
TeamGMATIFY wrote:
Bunuel wrote:
If v = (w)^2(y)(z), how many positive factors does v have?

(1) w, y and z are integers greater than 1
(2) w, y and z are distinct prime numbers


Given: v = (w)^2(y)(z)
Required: Number of positive factors of v

We can find the number of factors of N = (x^a)*(y^b)*(z^c) if x, y and z are different prime numbers.
Number of factors = (a+1)(b+ 1)(c+1)

Statement 1: w, y and z are integers greater than 1
If w,y and z are prime, we can find the number of factors. If they are not, we cannot find.
INSUFFICIENT

Statement 2: w, y and z are distinct prime numbers
This clearly tells us that w,y and z are distinct prime numbers.
Hence we can find the number of factors.
Number of factors = 3*2*2 = 12 (Not needed to calculate for the question)
SUFFICIENT

Option B




What if W is negative?
Statement 2 doesnot bound for any of the prime factors to be negative?
If they would have asked for the factors the above explanation is fine.
but they have specifically asked for positive and then both the possibilities must be considered.
Experts please help!!


Hello

The statement says: "w, y, z are distinct prime numbers". Prime numbers cannot be negative. They are only positive.
So 2, 3 are prime but -2 and -3 are not prime.
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Re: If v = (w)^2(y)(z), how many positive factors does v have? [#permalink] New post  27 Sep 2023, 13:29
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Re: If v = (w)^2(y)(z), how many positive factors does v have? [#permalink]
27 Sep 2023, 13:29
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