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Re: Twelve questions for Christoph! [#permalink]
7. i assume its transit days per package...

...then its 29 !
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Re: Twelve questions for Christoph! [#permalink]
Christoph,

would you like to explain 5, 7 and 10?

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Re: Twelve questions for Christoph! [#permalink]
allabout wrote:
Christoph,

would you like to explain 5, 7 and 10?

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5. 8c3(all combinations)-36(combinations left over)

7. (10*1+9*2+5*3+4x)/(24+x)=3

10. just insert the numbers and u will see the pattern:

g(2)=1
g(3)=1+2=3
g(4)=3+3=6
g(5)=6+4=10

diff is 2,3,4, etc..

now calc g(20) !
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Re: Twelve questions for Christoph! [#permalink]
[ Question 1 ] I have no OA.
[ Question 2 ] I have no OA.
[ Question 3 ] I have no OA.
[ Question 4 ] 2)
[ Question 5 ] 300
[ Question 6 ] 17
[ Question 7 ] 29
[ Question 8 ] 92.5%
[ Question 9 ] I have no OA.
[ Question 10 ] B. 190
[ Question 11 ] 20
[ Question 12 ] E
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Re: Twelve questions for Christoph! [#permalink]
gamjatang wrote:
[ Question 1 ] I have no OA.
[ Question 2 ] I have no OA.
[ Question 3 ] I have no OA.
[ Question 4 ] 2)
[ Question 5 ] 300
[ Question 6 ] 17
[ Question 7 ] 29
[ Question 8 ] 92.5%
[ Question 9 ] I have no OA.
[ Question 10 ] B. 190
[ Question 11 ] 20
[ Question 12 ] E


is question 10 right ? i answere D), which is wrong, but after recalculating, i get 191 ?

g(2)=1
g(3)=1+2=3
g(4)=3+3=6
g(5)=6+4=10

diff is 2,3,4, etc.. diff b/w g(19) and g(20) is 20 ! sum from 2 to 19 is 190 ! but now i have to add g(2), which is 1. i get 191 ! hm ?



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