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A circle inscribed in an equilateral triangle with side

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vivek123
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A circle inscribed in an equilateral triangle with side [#permalink] New post   31 Dec 2005, 23:18
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A circle inscribed in an equilateral triangle with side length 20. What is the area of inscribed circle?


No OA available. Just try!



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Re: A circle inscribed in an equilateral triangle with side [#permalink] New post   31 Dec 2005, 23:27
vivek123 wrote:
A circle inscribed in an equilateral triangle with side length 20. What is the area of inscribed circle?
No OA available. Just try!

draw a triangle by adding the mid point of each side of the equilateral triangle. this new trangle, also equilateral trangle, is inscribed in the circle. the side of the new equi trangle is 10.
so r = a/sqrt 3 = 10/sqrt(3)

Area of the circle = pi (10/sqrt(3))^2 = (100/3) (pi)
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Re: A circle inscribed in an equilateral triangle with side [#permalink] New post   01 Jan 2006, 17:45
another way to solve this could be...

draw perpendicular bisectors of each angle. They should meet at the centroid of the triangle which is the center of the circle. the radius of the circle is 1/3 the length of the bisector.

or

length of bisector x = [(20)^2-(10)^2]^1/2 = 300^1/2

area = pi*300*1/3*1/3 = 100pi/3
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Re: A circle inscribed in an equilateral triangle with side [#permalink] New post   01 Jan 2006, 17:48
Professor wrote:
vivek123 wrote:
A circle inscribed in an equilateral triangle with side length 20. What is the area of inscribed circle?
No OA available. Just try!

draw a triangle by adding the mid point of each side of the equilateral triangle. this new trangle, also equilateral trangle, is inscribed in the circle. the side of the new equi trangle is 10.
so r = a/sqrt 3 = 10/sqrt(3)

Area of the circle = pi (10/sqrt(3))^2 = (100/3) (pi)



Pls explain "so r = a/sqrt 3" how u got this with working
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Re: A circle inscribed in an equilateral triangle with side [#permalink] New post   01 Jan 2006, 18:09
for a equilateral triangle with side 20, the height of the equilateral triangle is 10sqrt3.

the radius of the inscribed circle within this equilateral traingle is 1/3 of the height of the traingle

so radius is (10sqrt3)/3 = 10/(sqrt3)

area of the inscribed circle = pi* [10/(sqrt3)]^2
= pi*100/3



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Thank you for understanding, and happy exploring!
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Re: A circle inscribed in an equilateral triangle with side [#permalink]
01 Jan 2006, 18:09
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