The King Edward College team won 25% of its first games and went on to

Responding to a pm:

I would use weighted averages concept here:

There are two groups: first games and rest of the games
First games - team won 25% of these
Rest games - team won 100% of these

First look at statement 2:

Stmnt 2: We know the average "won" percentage. So we can find the ratio of number of first games to number of rest of the games and hence the ratio of games won to games lost. You don't need to do those calculations but if you want to see them, here goes:
wF/wR = (100 - 75)/(75 - 25) = 1/2
First games : Rest games = 1:2 = 4:8 (for convenience - to calculate 25%, 75% etc)
The team won 25% of first games so 1 game and 100% of rest games so 8 games. In all, the team won 9 games and lost 3.
Ratio of won:lost = 3:1
Sufficient

Stmnt 1:
The team won 25% of its first games. If it had won 25% of all games, then it would have won 25% of rest of the games too. In that case, it would have lost 75% of the rest of the games extra which is given to be 30.
75% of Rest Games = 30
Rest of the games = 40
Now we still don't know how many games were there in the first lot.

Say there were 40 games in the first lot too.
Games won = 10 + 40 = 50
Games lost = 30
Ratio of won:lost = 5:3

Say there were 100 games in the first lost.
Games won = 25 + 40 = 65
Games lost = 75
Ratio of won:lost = 13:14

Not sufficient

Answer (B)

Hi Karishma,

Your answer is different from the OA, which is D.

Please find the same kind of question here m09-183831.html

By comparing these two questions, I am assuming that in the question it should have details regarding the number of first games.

That question and this question are different. That question gives you the number of games in the first lot.
"A chess player won 25 percent of the first 20 games he played and all of his remaining games"

This question does not. Without this information, statement 1 is not sufficient alone.

The answer here will not be (D). It will be (B). The original poster has put up incorrect OA.

The King Edward College team won 25% of its first games and went on to win all of its remaining games. What was the ratio of games won to the games lost by the team, if there were no ties?

(1)If team had won 25% of all its games, it would have lost 30 more games than it actually did.
(2)The team won 75% of all its games.

Responding to a pm:

I would use weighted averages concept here:

There are two groups: first games and rest of the games
First games - team won 25% of these
Rest games - team won 100% of these

First look at statement 2:

Stmnt 2: We know the average "won" percentage. So we can find the ratio of number of first games to number of rest of the games and hence the ratio of games won to games lost. You don't need to do those calculations but if you want to see them, here goes:
wF/wR = (100 - 75)/(75 - 25) = 1/2
First games : Rest games = 1:2 = 4:8 (for convenience - to calculate 25%, 75% etc)
The team won 25% of first games so 1 game and 100% of rest games so 8 games. In all, the team won 9 games and lost 3.
Ratio of won:lost = 3:1
Sufficient

Stmnt 1:
The team won 25% of its first games. If it had won 25% of all games, then it would have won 25% of rest of the games too. In that case, it would have lost 75% of the rest of the games extra which is given to be 30.
75% of Rest Games = 30
Rest of the games = 40
Now we still don't know how many games were there in the first lot.

Say there were 40 games in the first lot too.
Games won = 10 + 40 = 50
Games lost = 30
Ratio of won:lost = 5:3

Say there were 100 games in the first lost.
Games won = 25 + 40 = 65
Games lost = 75
Ratio of won:lost = 13:14

Not sufficient

Answer (B)

Stmnt 2: We know the average "won" percentage. So we can find the ratio of number of first games to number of rest of the games and hence the ratio of games won to games lost. You don't need to do those calculations but if you want to see them, here goes:
wF/wR = (100 - 75)/(75 - 25) = 1/2



You have clearly mentioned that there are two groups (which was not obvious from the question that there are two groups):
There are two groups: first games and rest of the games
First games - team won 25% of these
Rest games - team won 100% of these

Can you please elaborate the relation between "First, Rest, and All"

From the statement 2:
The team won 75% of ALL its games.

How did you arrive at the following:
We know the average "won" percentage.
So, we can find the ratio of number of first games to number of rest of the games
and hence the ratio of games won to games lost.

You don't need to do those calculations but if you want to see them, here goes:
wF/wR = (100 - 75)/(75 - 25) = 1/2

Here, WF/WR is the ratio of "Won in First/Won in Rest".

I did not understand the numbers that you have subtracted in the numerator and the denominator.
Please explain.
Thanks in advance.

Regards,
Yosita

Stmnt 2: We know the average "won" percentage. So we can find the ratio of number of first games to number of rest of the games and hence the ratio of games won to games lost. You don't need to do those calculations but if you want to see them, here goes:
wF/wR = (100 - 75)/(75 - 25) = 1/2



You have clearly mentioned that there are two groups (which was not obvious from the question that there are two groups):
There are two groups: first games and rest of the games
First games - team won 25% of these
Rest games - team won 100% of these

Can you please elaborate the relation between "First, Rest, and All"

From the statement 2:
The team won 75% of ALL its games.

How did you arrive at the following:
We know the average "won" percentage.
So, we can find the ratio of number of first games to number of rest of the games
and hence the ratio of games won to games lost.

You don't need to do those calculations but if you want to see them, here goes:
wF/wR = (100 - 75)/(75 - 25) = 1/2

Here, WF/WR is the ratio of "Won in First/Won in Rest".

I did not understand the numbers that you have subtracted in the numerator and the denominator.
Please explain.
Thanks in advance.

Regards,
Yosita

Responding to a pm:

I would use weighted averages concept here:

There are two groups: first games and rest of the games
First games - team won 25% of these
Rest games - team won 100% of these

First look at statement 2:

Stmnt 2: We know the average "won" percentage. So we can find the ratio of number of first games to number of rest of the games and hence the ratio of games won to games lost. You don't need to do those calculations but if you want to see them, here goes:
wF/wR = (100 - 75)/(75 - 25) = 1/2
First games : Rest games = 1:2 = 4:8 (for convenience - to calculate 25%, 75% etc)
The team won 25% of first games so 1 game and 100% of rest games so 8 games. In all, the team won 9 games and lost 3.
Ratio of won:lost = 3:1
Sufficient

Stmnt 1:
The team won 25% of its first games. If it had won 25% of all games, then it would have won 25% of rest of the games too. In that case, it would have lost 75% of the rest of the games extra which is given to be 30.
75% of Rest Games = 30
Rest of the games = 40
Now we still don't know how many games were there in the first lot.

Say there were 40 games in the first lot too.
Games won = 10 + 40 = 50
Games lost = 30
Ratio of won:lost = 5:3

Say there were 100 games in the first lost.
Games won = 25 + 40 = 65
Games lost = 75
Ratio of won:lost = 13:14

Not sufficient

Answer (B)

Hi Veritas , For St 2 do we need to calculate anything? If it won 75% then it means it lost 25%. So ratio is 3:1. Am I doing anything wrong? Thanks

HI All,

I think the ans is D and my explanantion is as follows for it

Let the total number of games be played be =100
Let x= First number of games played, Team won 25/100 X, team lost 75/100X and team won (100-X ) all its remaining games

Option 1 – If team had won 25% of all its games, it would have lost 30 more games than it actually did.

100 is the total number of games the team played we assumed, as per option1 , it won 25, lost 75 so

75 =30+75/100*X
Solve for X = 60
Total games lost is 75/100X as derived above = 45
Total games won is 25/100 X + 100-X =55

SO clearly A is also sufficient
B has already proved to be sufficient by other,

Answer should be D

VeritasKarishma chetan2u @Bunel - Can you guys confirm this

Regards