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Re: 2+2sqrt6)/2= A)SQRT6 B)2SQRT6 C)1+SQRT6 D)1+2SQRT6 [#permalink]
thearch wrote:
hedder02 wrote:
I'd say A. Can't the 2's cancel out leaving the sqrt 6?


try this if you've got a problem of this kind

(2*sqrt[4]+2)/2
is it 2?
or it is 3?

Since it is 3 and not 2, then your semplification is not correct. :good
''

thearch!!! what u concluding? wht is the ans? and u can call me raz
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Re: 2+2sqrt6)/2= A)SQRT6 B)2SQRT6 C)1+SQRT6 D)1+2SQRT6 [#permalink]
razrulz wrote:
thearch wrote:
hedder02 wrote:
I'd say A. Can't the 2's cancel out leaving the sqrt 6?


try this if you've got a problem of this kind

(2*sqrt[4]+2)/2
is it 2?
or it is 3?

Since it is 3 and not 2, then your semplification is not correct. :good
''

thearch!!! what u concluding? wht is the ans? and u can call me raz


Hi raz,
it is C for me as well! Sorry if my example wasn't clear...the point is: if you have sqrt[6], substitute it with a perfect square like 4, and change the answers thereof.
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Re: 2+2sqrt6)/2= A)SQRT6 B)2SQRT6 C)1+SQRT6 D)1+2SQRT6 [#permalink]
thearch wrote:
razrulz wrote:
thearch wrote:
hedder02 wrote:
I'd say A. Can't the 2's cancel out leaving the sqrt 6?


try this if you've got a problem of this kind

(2*sqrt[4]+2)/2
is it 2?
or it is 3?

Since it is 3 and not 2, then your semplification is not correct. :good
''

thearch!!! what u concluding? wht is the ans? and u can call me raz


Hi raz,
it is C for me as well! Sorry if my example wasn't clear...the point is: if you have sqrt[6], substitute it with a perfect square like 4, and change the answers thereof.


thnks buddy u made my day! :) i got one right! hurray!!!! lets party
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Re: 2+2sqrt6)/2= A)SQRT6 B)2SQRT6 C)1+SQRT6 D)1+2SQRT6 [#permalink]
Good Job OA is C
2/2 + 2sqrt6/2 = 1+sqrt6



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