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John and Tom leave the school at the same time to each of their houses

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MathRevolution
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John and Tom leave the school at the same time to each of their houses [#permalink] New post   13 Feb 2017, 01:00
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E

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John and Tom leave the school at the same time to each of their houses. Does John reach his house faster than Tom?

1) The distance between the school and John’s house is 10km farther than the distance between the school and Tom’s house
2) Tom’s speed is 80% of John’s speed.
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rohit8865
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Re: John and Tom leave the school at the same time to each of their houses [#permalink] New post   13 Feb 2017, 03:16
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MathRevolution wrote:
John and Tom leave the school at the same time to each of their houses. Does John reach his house faster than Tom?

1) The distance between the school and John’s house is 10km farther than the distance between the school and Tom’s house
2) Tom’s speed is 80% of John’s speed.



Good Question.!!

answer will be C or E.

combining we know that speed of tom (t) = 0.8 John speed =0.8 J
also distance from school to Tom house is = X(let)
then distance of Johns home =x+10

per question is Time taken by John < time taken by TOm ??
as time = Distance / speed

x+10/j < x/0.8j

or is x>40

but we dont know that ie distance betwee tom house to school may be 20 then ans will be No or if distance will be 60 units then ans will be YES
combining is still insuff

Ans E
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Re: John and Tom leave the school at the same time to each of their houses [#permalink] New post   15 Feb 2017, 01:07
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==> In the original condition, there are 5 variables (v1, t1, v2, t2, d) and 2 equations (v1t1=d and v2t2=d), and in order to match the number of variables to the number of equations, there must be 3 more equations. Since there is 1 for con 1) and 1 for con 2), E is most likely to be the answer. By solving con 1) and con 2), you cannot find the value of d, hence it is not sufficient.

The answer is E.
Answer: E
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Re: John and Tom leave the school at the same time to each of their houses [#permalink] New post   24 Oct 2020, 06:24
MathRevolution wrote:
John and Tom leave the school at the same time to each of their houses. Does John reach his house faster than Tom?

1) The distance between the school and John’s house is 10km farther than the distance between the school and Tom’s house
2) Tom’s speed is 80% of John’s speed.


Got it incorrect, selected C, as I rushed instead of checking what the data may imply.

The data when combined still gives us two variables.
Time taken by John = D/S = [t +10/ 1.25s] (where t = distance of Tom’s house from school, and s = speed of Tom)
Time taken by Tom = D/S = t/s.

Therefore, we cannot produce a unique solution with 2 variables.
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Re: John and Tom leave the school at the same time to each of their houses [#permalink] New post   24 Oct 2020, 11:06
Combining two statements ... I reached till below point.

Is x=X/0.8Y > X+10/Y .. where Y is speed of John and X is the Distance from School to house for tom.
For any positive values of X and Y the Lhs will be lower than RHS of the above eqn.

Where i am Wrong ???
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Re: John and Tom leave the school at the same time to each of their houses [#permalink] New post   28 Oct 2020, 04:42
Hi, I think the question should be fixed. The question asks if Jhon reaches his house faster than Tom. In this sense, it doesn´t matter who arrives first, what the question is asking is who walked faster. Statement 2 should be sufficient to answer this. On the other hand, if the question asked who arrived first or earlier it would make sense that option E be correct. Please let me know if you see any flaw in this and thank you!
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Re: John and Tom leave the school at the same time to each of their houses [#permalink] New post   16 Jan 2023, 12:19
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Re: John and Tom leave the school at the same time to each of their houses [#permalink]
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