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Re: A wheel that has a radius of 24 rotates 270 degrees. How [#permalink]
Diameter = pi * 24* 2 = 48pi

This is equivalent to 360 degress rotation.

So 270 degrees will give you 270/360 * 48pi = 36pi
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Re: A wheel that has a radius of 24 rotates 270 degrees. How [#permalink]
Professor wrote:
getzgetzu wrote:
A wheel that has a radius of 24 rotates 270 degrees. How long did an edge point move?


= (270/360) pi (24)^2
= (3) pi (24x6)
= 432 pi


Prof, you've gone for area instead of diameter :lol:
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Re: A wheel that has a radius of 24 rotates 270 degrees. How [#permalink]
ywilfred wrote:
Professor wrote:
getzgetzu wrote:
A wheel that has a radius of 24 rotates 270 degrees. How long did an edge point move?


= (270/360) pi (24)^2
= (3) pi (24x6)
= 432 pi


Prof, you've gone for area instead of diameter :lol:


i was wonding why people make mistakes. now i realize why i make mistakes..

yes i went after area instead of perimeter. :wink: :wink: :wink:

Originally posted by Professor on 17 May 2006, 20:28.
Last edited by Professor on 18 May 2006, 05:14, edited 1 time in total.
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Re: A wheel that has a radius of 24 rotates 270 degrees. How [#permalink]
yea 36 pi looks good
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Re: A wheel that has a radius of 24 rotates 270 degrees. How [#permalink]
circumference - 2piR = 48pi
therefore the wheel moves 48pi in 360 deg
Hence it will move 270/360 * 48pi = 36 pi in 270 deg
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Re: A wheel that has a radius of 24 rotates 270 degrees. How [#permalink]
For 1 rotation ie. 360 degrees, the wheel moves 2*pi*r .
For 270 degrees it moves (270*48*pi)/360 = 36 pi



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