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A school club plans to package and sell dried fruit to raise money. Th

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carcass
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A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   23 Jul 2017, 10:50
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A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804
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E
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   24 Jul 2017, 00:37
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carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804


12 containers of dried fruit, each containing \(16\frac{3}{4}=\frac{67}{4}\) pounds = \(\frac{12*67}{4}\) pounds.

\(\frac{(\frac{12*67}{4})}{(\frac{1}{4})}=\frac{12*67}{4}*4=12*67=...4\) (something with units digit of 4 but for sure greater than 64, gives only E).

Answer; E.
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   23 Jul 2017, 15:35
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carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing 16 \(\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?

A. 50

B. 64

C. 67

D. 768

E. 804

Total pounds of dried fruit:
12 containers * 16\(\frac{3}{4}\) lbs / container =
(12*16) + (12*\(\frac{3}{4}\)) =
(192 + 9) = 201 pounds

How many quarter-pound bags can be made from 201 total pounds?

\(\frac{201}{(\frac{1}{4})\) = 201 * 4 = 804

Answer E
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   23 Jul 2017, 15:49
carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing 16 \(\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?

A. 50

B. 64

C. 67

D. 768

E. 804


I. 12 packs containing 16.75 lbs each: Total = 12*16.75 lbs
II. Total/(1/4) = Total*4 = (12*16.75)*4 = [12*16+12*3/4]*4 = [201]*4 = 804 bags
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   24 Jul 2017, 10:35
option E
3/4 part of the 16 will give 3 bags.
1 pound will give 4.
Total is 16. So 16*4+3=67
Now 67 *12= 804 bags
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   24 Jul 2017, 10:41
\(12 * (\frac{3}{4} * 4 + 16 * 4) = 12 * (3+64) = 804\). Ans - E.
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   24 Jul 2017, 10:54
carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804


I would do 67/4 * 12* 4= 201*4= 804, E.
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   26 Jul 2017, 16:17
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carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804


The total fruit purchased, in pounds, was:

12 x 16 ¾ = 12 x 67/4 = 3 x 67 = 201

Thus, the number of bags of fruit, each containing 1/4 pounds, that can be sold is:

201/(1/4) = 201 x 4 = 804

Answer: E
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   24 Apr 2018, 03:05
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QA E ,
12*67/4 = 804/4/1/4 = 804
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   14 Aug 2018, 03:47
Let the maximum number of individual bags of dried fruit, each containing 1/4 pounds be "B"
1/4*B=67/4*12 (as total weight of dried fruits=67/4*12 pounds)
B=804

Answer (E)
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   19 Aug 2018, 21:34
1 container weight = 67/4 pounds
12 containers weight = 67*12/4 = 201 pounds
Number of packges that can be made of 1/4 pounds = 201/(1/4) = 201*4 = 804

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A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   20 Oct 2018, 04:02
carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804


\(16\frac{3}{4}\) = \(\frac{67}{4}\) and \(\frac{67}{4}* 12 = 201\)

Basically 1 pound makes 4 bags (because bag takes \(\frac{1}{4}\) pounds)

Multiply 201 by 4 = 804

Answer choice E
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   01 Mar 2019, 11:42
Hi, we can solve this alternatively

if we assume that each lot contains 17 pounds.

Then total we have is 17 *12.

We need to distribute them in bags which can hold upto 1/4 pounds.

the total number of bags in this case would be 17*12*4= 816

Since we have taken 1/4 more than given lot size , the additional bags because of these 1/4 is = 1/4*12*4 = 12

So total number of bags are 816-12= 804


Hope this helps
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   25 Sep 2019, 23:10
carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804


I think the most logical and easiest approach is

16 3/4 = 16.75 (as 1/4 = .25 so 3/4 = .75)
12 * 16.75 (i.e total bags *dry fruits in 1 bag = total dry fruits ) = 201

step 2
now I have total dry fruits 201 and a pouch should have 1/4 dry fruits so how many such bags would be there
201 = 1/4 * x (where X is total no. of pouch with 1/4 dry fruits in each pouch ) => 804 ans E
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   09 Oct 2020, 07:59
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carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804


I did altogether in a raw:
12x(67/4)x4/1 = 67x 12= 804
Ans E.
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   08 Nov 2020, 12:25
16 3/4 = 67/4

67/4 * 12 = 201

201 * 4 = 804

Answer is E.
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   09 Nov 2020, 15:13
Quick way (!)
The result must be divisible by 12, therefore, by 3. E is the only divisible by 3
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A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   13 May 2022, 10:52
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carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?

A. 50
B. 64
C. 67
D. 768
E. 804

Probus wrote:
Hi, we can solve this alternatively

if we assume that each lot contains 17 pounds.

Then total we have is 17 *12.

We need to distribute them in bags which can hold upto 1/4 pounds.

the total number of bags in this case would be 17*12*4= 816

Since we have taken 1/4 more than given lot size , the additional bags because of these 1/4 is = 1/4*12*4 = 12

So total number of bags are 816-12= 804


Hope this helps



You and I are on the same page, Probus. Why would I work with 64/7 unless absolutely necessary?!?

One little tweak for me. I don't like 17. It's just not a number that feels great for me to work with. So, I went with 16. Since I've rounded down, I'll put a little (+) next to each step in my calculations to remind me that I need an answer choice that's a little bigger than what I've got.

16*12 = 160+32 = 192(+)
Now I need to multiply that by 4, so 192*4, which is 768(+).

There's only one answer choice that's a little bigger than the 768 I got.

Answer choice E.

ThatDudeKnowsBallparking
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Re: A school club plans to package and sell dried fruit to raise money. Th [#permalink] New post   21 Jun 2023, 08:49
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