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Re: Are negative integers s and t both less than t? 1) s < r+t 2)[m][fract [#permalink]
Expert Reply
gmatbusters wrote:
Are negative integers \(s\) and \(t\) both less than \(r\) ?
1) \(s < r+t\)
2)\(\frac{s}{r}\)\(<t\)


Similar question to practice: https://gmatclub.com/forum/are-negative ... 25947.html
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Are negative integers s and t both less than t? 1) s < r+t 2)[m][fract [#permalink]
EgmatQuantExpert wrote:

Solution



Given:
• Both s and t are negative integers

To find:
• Whether the value of s and t less than r

Analysing Statement 1
• As per the information given in Statement 1, s < r + t
    o Or, r > s – t
• As it is given that both s and t are negative integers, if we assume that s is less than t, we can have the following scenario possible for r:



Depending on the values of s and t, r can belong to any of the regions indicated.
For example, if s = -7 and t = -1, r > (-7) – (-1) or r > -6
Now, r > -6 means r belong to any of the 3 regions indicated above (red, blue, green)

Hence, statement 1 is not sufficient to answer

Analysing Statement 2
As per the information given in Statement 2, \(\frac{s}{r}\) < t
    o Or, r > \(\frac{s}{t}\)

• As both s and t are negative integers, the ratio of s and t are always positive.
    o Given that r is greater than s/t means r is also positive
    o Hence, r is always greater than s and t

Hence, statement 2 is sufficient to answer

Hence, the correct answer is option B.

Answer: B


Hi EgmatQuantExpert

May be I am missing something here. kindly explain the highlighted part. how are we arriving at \(r>\frac{s}{t}\). we know \(t\) is negative and we know nothing about \(r\). so if you are cross-multiplying \(t\) then sign of inequality should change.

Eventually \(r\) will be positive.
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Re: Are negative integers s and t both less than t? 1) s < r+t 2)[m][fract [#permalink]
Expert Reply
Hi

The best approach to consider statement 2 is as follows:

2) s/r <t
as we know that s and t are negative,
So if r is also negative, then s/r would be positive and this inequality s/r <t would not be valid .
So r is positive. hence s and t are both less than r .

SUFFICIENT.

niks18 wrote:
EgmatQuantExpert wrote:

Solution



Given:
• Both s and t are negative integers

To find:
• Whether the value of s and t less than r

Analysing Statement 1
• As per the information given in Statement 1, s < r + t
    o Or, r > s – t
• As it is given that both s and t are negative integers, if we assume that s is less than t, we can have the following scenario possible for r:



Depending on the values of s and t, r can belong to any of the regions indicated.
For example, if s = -7 and t = -1, r > (-7) – (-1) or r > -6
Now, r > -6 means r belong to any of the 3 regions indicated above (red, blue, green)

Hence, statement 1 is not sufficient to answer

Analysing Statement 2
As per the information given in Statement 2, \(\frac{s}{r}\) < t
    o Or, r > \(\frac{s}{t}\)

• As both s and t are negative integers, the ratio of s and t are always positive.
    o Given that r is greater than s/t means r is also positive
    o Hence, r is always greater than s and t

Hence, statement 2 is sufficient to answer

Hence, the correct answer is option B.

Answer: B


Hi EgmatQuantExpert

May be I am missing something here. kindly explain the highlighted part. how are we arriving at \(r>\frac{s}{t}\). we know \(t\) is negative and we know nothing about \(r\). so if you are cross-multiplying \(t\) then sign of inequality should change.

Eventually \(r\) will be positive.
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Re: Are negative integers s and t both less than t? 1) s < r+t 2)[m][fract [#permalink]
Expert Reply
Hi niks18

Your Query: May be I am missing something here. kindly explain the highlighted part. how are we arriving at \(r>\frac{s}{t}\). we know \(t\) is negative and we know nothing about \(r\). so if you are cross-multiplying \(t\) then
sign of inequality should change.- Since we don't know the nature of r, we can not predict the nature of sign of inequality at this stage of time, without determining the nature of sign of r..
niks18 wrote:

Solution

[/color]

Given:
• Both s and t are negative integers

To find:
• Whether the value of s and t less than r

Analysing Statement 1
• As per the information given in Statement 1, s < r + t
    o Or, r > s – t
• As it is given that both s and t are negative integers, if we assume that s is less than t, we can have the following scenario possible for r:



Depending on the values of s and t, r can belong to any of the regions indicated.
For example, if s = -7 and t = -1, r > (-7) – (-1) or r > -6
Now, r > -6 means r belong to any of the 3 regions indicated above (red, blue, green)

Hence, statement 1 is not sufficient to answer

Analysing Statement 2
As per the information given in Statement 2, \(\frac{s}{r}\) < t
    o Or, r > \(\frac{s}{t}\)

• As both s and t are negative integers, the ratio of s and t are always positive.
    o Given that r is greater than s/t means r is also positive
    o Hence, r is always greater than s and t

Hence, statement 2 is sufficient to answer

Hence, the correct answer is option B.

Answer: B


Hi EgmatQuantExpert

May be I am missing something here. kindly explain the highlighted part. how are we arriving at \(r>\frac{s}{t}\). we know \(t\) is negative and we know nothing about \(r\). so if you are cross-multiplying \(t\) then sign of inequality should change.

Eventually \(r\) will be positive.[/quote]
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Re: Are negative integers s and t both less than t? 1) s < r+t 2)[m][fract [#permalink]
Expert Reply
niks18 wrote:

Hi EgmatQuantExpert

May be I am missing something here. kindly explain the highlighted part. how are we arriving at \(r>\frac{s}{t}\). we know \(t\) is negative and we know nothing about \(r\). so if you are cross-multiplying \(t\) then sign of inequality should change.

Eventually \(r\) will be positive.


Hi niks,
You are correct! We cannot infer anything about the range of r. Ideally we can only say that:
    • As both s and t are negative integers, the right-hand side of the given expression is negative. But \(\frac{s}{t}\) is positive.
    • Given that s is also negative, it means r is positive
Hence, from the given statement \(\frac{s}{r}\) < t, we can say r > 0 and \(\frac{s}{t}\) > 0

Have edited the solution. Apologies for the confusion.
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Re: Are negative integers s and t both less than t? 1) s < r+t 2)[m][fract [#permalink]
1) s<r+t

Remember we don't know sign of r
So multiple cases arise
1) -6<-2-3
s=-6 r=-2 t=-3. S and t are less than r

2)-6<-3-2
s=-6 r=-3 t=-2. S is less than r but t is not

So Insufficient


2)s/r<t

S and t are given as negative integers

R cannot be negative here as it would result in positive value on left side
Whereas on the left side we have negative value

So r is positive and t and s are less than r as they are negative

Sufficient

B is answer

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Re: Are negative integers s and t both less than t? 1) s < r+t 2)[m][fract [#permalink]
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