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Re: If a is a positive integer, is b also a positive integer? [#permalink]
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Bunuel wrote:
If a is a positive integer, is b also a positive integer?

(1) The average (arithmetic mean) of a, b + 2, and a - 5 is a.

(2) The average (arithmetic mean) of a and b is NOT a positive integer.



(Statement 1) \(\frac{a+b+2+a-5}{3}=a\). Therefore, \(b=a+3\). \(b\) is positive. Statement 1 is Sufficient.

(Statement 2). Assume a = 4, b= 3, average will be 3.5 . average is NOT a positive integer, but b is a positive integer.
Assume a = 4, b= 5.2, average will be 4.6 . average is NOT a positive integer, and b is NOT a positive integer.

Therefore,

(A) Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Hence option A is the answer.
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Re: If a is a positive integer, is b also a positive integer? [#permalink]
houston1980 wrote:
Bunuel wrote:
If a is a positive integer, is b also a positive integer?

(1) The average (arithmetic mean) of a, b + 2, and a - 5 is a.

(2) The average (arithmetic mean) of a and b is NOT a positive integer.



(Statement 1) \(\frac{a+b+2+a-5}{3}=a\). Therefore, \(b=a+3\). \(b\) is positive. Statement 1 is Sufficient.

(Statement 2). Assume a = 4, b= 3, average will be 3.5 . average is NOT a positive integer, but b is a positive integer.
Assume a = 4, b= 5.2, average will be 4.6 . average is NOT a positive integer, and b is NOT a positive integer.

Therefore,

(A) Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Hence option A is the answer.


Missed one subtle point: 'positive INTEGER'. Perfect explanation.
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If a is a positive integer, is b also a positive integer? [#permalink]
Tulkin987 wrote:
houston1980 wrote:
Bunuel wrote:
If a is a positive integer, is b also a positive integer?

(1) The average (arithmetic mean) of a, b + 2, and a - 5 is a.

(2) The average (arithmetic mean) of a and b is NOT a positive integer.



(Statement 1) \(\frac{a+b+2+a-5}{3}=a\). Therefore, \(b=a+3\). \(b\) is positive. Statement 1 is Sufficient.

(Statement 2). Assume a = 4, b= 3, average will be 3.5 . average is NOT a positive integer, but b is a positive integer.
Assume a = 4, b= 5.2, average will be 4.6 . average is NOT a positive integer, and b is NOT a positive integer.

Therefore,

(A) Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Hence option A is the answer.


Missed one subtle point: 'positive INTEGER'. Perfect explanation.



Actually, there is other case to provide insufficiency. It may help you to consinder in other questions.

Let a = 1 & b=0 ..mean = 1/2....b is integer but neither positive nor negative (character of zero)
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If a is a positive integer, is b also a positive integer? [#permalink]
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