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Re: What is the area of a triangle whose sides are formed by the x−axis [#permalink]
Base of triangle on x-axis= x intercept= 12

Height of triangle on y-axis= y intercept= 9

Area of triangle= (9*12)/2= 54

Ans D

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Re: What is the area of a triangle whose sides are formed by the x−axis [#permalink]
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Bunuel wrote:
What is the area of a triangle whose sides are formed by the x−axis, the y−axis, and the line \(y = −\frac{3}{4}x + 9\)?

A. 6
B. 18
C. 36
D. 54
E. 72


This is the equation of line. Let's change it to intercept form so that x and y intercepts can be calculated easily.
\(y = −\frac{3}{4}x + 9\)

\(y + \frac{3}{4}x = 9\)

\(\frac{y}{9} + \frac{3}{4.9}x = 1\).

\(\frac{y}{9} + \frac{x}{12} = 1\).

Now Line intersects the x axis at (12,0) and Y axis at (0,9).

If you could imagine a line passing thru these points (12,0) ,(0,9) ,x axis and y-axis.
Height & base of Triangle is 9 & 12. You can also consider vice-versa.

Area of Triangle = \(\frac{1}{2} * 12* 9 = \frac{108}{2}\)= 54.

Ans - D
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Re: What is the area of a triangle whose sides are formed by the x−axis [#permalink]
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