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If a > 0, what is the value a^xa^y ? (1) x = -y (2) a = -2 and x - y=6

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If a > 0, what is the value a^xa^y ? (1) x = -y (2) a = -2 and x - y=6 [#permalink] New post   Updated on: 10 Nov 2018, 06:27
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If \(a > 0\), what is the value \(a^xa^y\) ?


(1) \(x = -y\)

(2) \(a = -2\) and \(x - y = 6\)

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Originally posted by AkshdeepS on 20 Jun 2018, 11:17.
Last edited by Bunuel on 10 Nov 2018, 06:27, edited 1 time in total.
Renamed the topic and edited the question.
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Re: If a > 0, what is the value a^xa^y ? (1) x = -y (2) a = -2 and x - y=6 [#permalink] New post   20 Jun 2018, 13:24
clear A


2 NOT SUFF AS WE NEED X+Y
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Re: If a > 0, what is the value a^xa^y ? (1) x = -y (2) a = -2 and x - y=6 [#permalink] New post   20 Jun 2018, 13:56
Is that a typo?
Condition is a > 0 but statement 2 says a = -2

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Re: If a > 0, what is the value a^xa^y ? (1) x = -y (2) a = -2 and x - y=6 [#permalink]
20 Jun 2018, 13:56
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