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(4^5 + 4^3)/4^2

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KSBGC
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(4^5 + 4^3)/4^2 [#permalink] New post   Updated on: 22 Jun 2018, 22:25
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80% (00:37) correct 20% (00:55) wrong based on 54 sessions
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\(\frac{(4^5+4^3)}{4^2} =\)


A. \(4^2\)

B. \(4^3\)

C. \(4^3+4\)

D. \(4^4\)

E. \(4^6\)
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C

Originally posted by KSBGC on 22 Jun 2018, 14:45.
Last edited by Bunuel on 22 Jun 2018, 22:25, edited 2 times in total.
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Re: (4^5 + 4^3)/4^2 [#permalink] New post   22 Jun 2018, 16:11
\(4^5\)+\(4^3\)/\(4^2\) =

Hi,

Please correct the errot, the equation has to be \((4^5\)+\(4^3\))/\(4^2\)
Otherwise only \(4^3\) is devided by \(4^2\)
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Re: (4^5 + 4^3)/4^2 [#permalink] New post   22 Jun 2018, 20:14
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selim wrote:
(\(4^5\)+\(4^3\))/\(4^2\) =

A.\(4^2\)
B. \(4^3\)
C.\(4^3\)+4
D. \(4^4\)
E.\(4^6\)


(\(4^5\)+\(4^3\))/\(4^2\) =\(\frac{4^3(4^2+1)}{4^2}\)
=>\(4(4^2+1)=4^3+4\)

OR
\(\frac{(4^5+4^3)}{4^2}=\frac{4^5}{4^2}+\frac{4^3}{4^2}=4^{5-2}-4^{3-2}=4^3+4\)

C
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BrentGMATPrepNow
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Re: (4^5 + 4^3)/4^2 [#permalink] New post   23 Jun 2018, 05:53
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selim wrote:
\(\frac{(4^5+4^3)}{4^2} =\)


A. \(4^2\)

B. \(4^3\)

C. \(4^3+4\)

D. \(4^4\)

E. \(4^6\)


Often-tested rule: (a + b)/c = a/c + b/c

So, (4^5 + 4^3)/4^2 = (4^5)/4^2 + (4^3)/4^2
= 4^3 + 4^1
= 4^3 + 4

Answer: C

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Re: (4^5 + 4^3)/4^2 [#permalink]
23 Jun 2018, 05:53
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