At a college party, 70% of the women are wearing red t-shirts. If 60%

Hi Kunal

Thanks for the reply.
Given data is 70% of women are wearing Red t shirts. So I assume this means there are x women and 70% of x are wearing Red t-shirts. So we really don't have the value of x women.
I hope my concern is clear. Correct me if I'm wrong

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Hi Akash720
You are right i misread the question.

Hi,

I will go with A.
At a college party, 70% of the women are wearing red t-shirts. If 60% of the people at the party are wearing red t-shirts, what is the ratio of women to men at the party?

(1) Forty percent of the men at the party are wearing red t-shirts.

(2) There are 120 people at the party.

Let Men be "x" and Women be "y". It says that 70% of women are wearing red t-shirts i.e. 7y/10. 60% of the people are wearing red t-shirts i.e. 3(x+y)/5.
1.2x/5 men are wearing red t-shirt. Hence, 2x/5 + 7y/10 = 3(x+y)/5. you get y/x= 2. Sufficient.

2. Insufficient. It just tells (x+y)=120. Doesn't tell anything about either percentage or number of men wearing red t-shirt.

Correct me if i am wrong in my approach.

No of women at party: W
No of men at party: M

No of women wearing Red t shirt: Wr
No of men wearing Red t shirt: Mr

Total No of people at party:W+M

Now,

Given:
70% of the women are wearing red t-shirts : \(Wr=\frac{70W}{100}\) .....................................(1)
60% of the people at the party are wearing red t-shirts : \((Wr+Mr)=\frac{60(W+M)}{100}\) ......(2)

To Calculate:
\(\frac{W}{M}\)

Statement1: Forty percent of the men at the party are wearing red t-shirts.
Therefore, \(Mr=\frac{40M}{100}\)
Adding (1) to Mr above:
(Wr+Mr) = \(\frac{70W}{100}+\frac{40M}{100}\)
=\(\frac{(7W+4M)}{10}\)

Equating the above equation with (2)
We get, \((7W+4M)=6(W+M)\)
This implies, W=2M
or, \(\frac{W}{M}=2\)
Sufficient.

Statement1: There are 120 people at the party
Therefore, M+W=120
We need either M or W to solve this equation. We have neither.
Hence, InSufficient.

Hence, the Answer is A