What is the average (arithmetic mean) annual salary of the 6 employees

ashisplb why would anyone do a job for zero salary ?
In fact it could be any value for the least paid and the increment of 6300 then on

Hey sudarshan22,
I liked your thought process.
Why would anyone will do a job with no salary?

ashisplb - jokes apart. Good explanation.

jackspire
SC alert : The above highlighted sentence is incorrect as per SC standards though, "would" and "will" together - Duhhhh

Jokes apart, Thanks much.

Hey sudarshan22,
Thanks for the correction.

Hi,

Stmt1 : Lets say we try to find the salary of six emp. Then it can be calculated by X(n)=X(n-1)+ 6300
So the sixth salary will be X(6)=X(1)+5(6300)
or X(6)-X(1)= 31,500
Insufficient.

Since 1 and 2 are both the same statements, So choice E

Probus

The average = Sum of salaries/6

Let first salary be x

The next salary will be x + 6,300 and so it goes to the 6th salary that equals x + 6,300*5

We have one variable that we don't know

Insufficient.

Statement 2)

Tells us the range X6 - X1 = 31,500

So we don't have anything specific about the salaries. Insufficient.

Now combine

The range is basically X6 - X1 = x + 6,300 *5 - x = 31,500

Basically tautology.

We don't know the value of x.

Insufficient.

Answer choice E

Statement (1) basically says " the range is 31500. We should paraphrase the disguise language. If both statement says the same thing then the answer must be (D) or(E)

Posted from my mobile device

(1) If the 6 annual salaries were ordered from least to greatest, each annual salary would be $6,300 greater than the preceding annual salary. insufic

ap: a+d(n-1)…
set: d,a+d,a+2d,a+3d,a+4d,a+5d
(a+d)-a=6300, d=6300

(2) The range of the 6 annual salaries is $31,500. insufic

(1&2) insufic

(a+5d)-a=31500, 5d=31500, d=6300; no info about 'a'

Ans (E)

Even from a guy who's terrible at quant (scored Q28 in my latest mock), this supposedly hard question is incredibly straightforward:

Statement 1 clearly doesn't provide any information that is necessary to find the average, we can just determine the gap between each salary: insufficient.
Statement 2: Just giving the range will give us the extreme salaries, but what about the 3 others? Insufficient as well!

Statements 1 & 2 together: 2 possible choices can result from this choice, so it's insufficient!

E for the win, solved in 40 seconds!

Statement 1:-
let the least salary be X
now total salary will be =X+ X+6300 + X +12600..................
We can not find X
in sufficient

Statement Two
Insufficient as we only know the diff of salary between highest and lowest

Both:-
Again Insufficient

What is the average (arithmetic mean) annual salary of the 6 employees of a toy company?

(1) If the 6 annual salaries were ordered from least to greatest, each annual salary would be $6,300 greater than the preceding annual salary.

This statement doesn't tell us anything. Is the least salary $1? $6,300? We aren't able to determine this -- we only know that each salary is $6,300 than the preceding salary. INSUFFICIENT.

(2) The range of the 6 annual salaries is $31,500.

This statement tells us the Same thing as statement 1. INSUFFICIENT.

(1&2) We have two statements that provide THE same information. INSUFFICIENT.

(1) We can't determine total salary to determine average; Insufficient.

(2) We don't know the highest and the lowest figure; Insufficient.

Considering both:
If the lowest is x and the highest is x+37,800, Even though we can't establish an equation (x+37,800-x=31,500; 0=31,500); Insufficient

The answer is E.

(1) If the 6 annual salaries were ordered from least to greatest, each annual salary would be $6,300 greater than the preceding annual salary. --- it's an AP with a common difference of 6300

let \(a1= x\)
\(an=a1+ (n-1)d\)
\(n=6\)
\(a6=x+6300(5)= x+ 31,500\)

In an evenly spaced set, mean = \(a1+a6/2\)= \(x+(x+31500)/2\)= \(2x+31500/2 \)this is as simplified as it can get. clearly without knowing x we can't go forward. Insuff.

(2) The range of the 6 annual salaries is $31,500

this is telling us more or less the same thing as the above one. \(a6-a1= 31500\)
if \(a1=x\)
\(a6= x+31500\)

we will get back the same equation:

Arithmetic mean = \(a1+a6/2\)= \(x+(x+31500)/2\)= \(2x+31500/2 \)


Insufficient.

1+2 since we get the same info from both, we can hardly use the combo for something new. C is easy to eliminate.

we're left with E.

not going to lie, I thgt, there must be some way we could get AM, by either of these statements. but sadly, that isn't the case.

Can anyone help me with this, I think the answer should be C, (after solving it).

Tag someone to answer you Bunuel

Posted from my mobile device

Target question: What is the average (arithmetic mean) annual salary of the 6 employees of a toy company?

When I scan the two statements, they both feel insufficient, AND I’m pretty sure I can identify some cases with conflicting answers to the target question. So, I’m going to head straight to……

Statements 1 and 2 combined
There are infinitely many scenarios that satisfy BOTH statements. Here are two:
Case a: The six salaries are $6,300, $12,600, $18,900, $25,200, $31,500 and $37,800 (note: range = $37,800 - $6300 = $31,500). In this case, the answer to the target question is the average annual salary is $22,050
Case b: The six salaries are $12,600, $18,900, $25,200, $31,500, $37,800 and $44,100 (note: range = $44,100 - $12,600 = $31,500). In this case, the answer to the target question is the average annual salary is $28,350
Since we can’t answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer: E

Cheers,
Brent

BrentGMATPrepNow
To see if my approach is correct, I realized that both statements say the same thing.
For statement 2, I did:
# 1: n + 6,300
# 2: (n + 6,300) + 6,300
# 3: (n + 6,300) + 6,300 + 6,300
# 4: ...
# 5: ...
# 6: (n + 6,300) + (6,300*5)

Then I took the range of these six numbers --> (n +6,300) - [(n+6,300) + (6,300*5) = 31,500 --> 31,500 = 31,500
I ruled it off on this basis because we already know from statement 1 that any value can be taken on.

Thank you in advance for your help