PKN wrote:
Shruti0805 wrote:
PKN wrote:
[quote="Bunuel"]If a triangle inscribed in a semicircle has area 40, what is the area of the circle?
(1) One side of the triangle is equal to the diameter of the circle.
(2) The measure of one of the angles in the triangle is 30.
Question stem:- we need the radius of circle in order to determine area of circle.
Given , a triangle is inscribed in a semicircle . By virtue of its property, 2 of the 3 vertices of the traingle lie on the extreme points of the diameter of the semicircle. Therefore , st1 is a repeat of the inherent property of *a triangle inscribed in a semicircle*
Hence st1 insufficient.
St2:- The triangle is a special right angled triangle of the form 30-60-90.
Area of the triangle is given. Hence radius of the semicircle can be calculated.
Sufficient.
(Sides of the triangle are in the ratio r:√3r:2r. Hence area=1/2*r*√3r=40. Value of r can be determined,actual computation is a waste of precious time)
Ans. (B)
Hi,
From statement 2, aren't you assuming that the 3 angle measures are 30, 60 and 90?
The statement mentions 1 angle is 30, the others could be of any combination summing up to 150.
I think only when we combine stmt 1 and 2 we can derive that its a right triangle and thus the angles would be 30/60/90 and eventually calculate the diameter and area of the circle.
Should be C in my view.
Hi
Shruti0805 ,
Why st1 is insufficient is already explained.
Refer red-highlightes line in your post. It's incorrect, rather st2 says one of the angle of the triabgle is 30 degree.
You know, any diameter of a circle subtends a right angle to any point on the circle.
Now we know two angles of the triangle( 90 and 30 degree) , so th emeasure of the third side is 180-90-30=60 degree
Hence the triangle is in the form 30-60-90.
Hope it's clear.[/quote]Hi,
Statement 2 doesn't really mention that the entire diameter is being used as a side. We could use just a smaller part of the diameter as a side and form a triangle that doesn't have its 3rd vertex on the edge of the circle, right? That creates a triangle which isn't a right triangle and makes this statement insufficient.
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