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Re: There are three fair dice rolled alltoghether. What is the [#permalink]
P=1–P(all three ARE the same)

P(same)=6*(1/6*1/6*1/6)=6/216=1/36

P(three ARE NOT the same)=1–1/36=35/36
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Re: There are three fair dice rolled alltoghether. What is the [#permalink]
There are three fair dice rolled alltoghether. What is the probability that the gotten numbers will all not be the SAME?

Does this not mean all the three dices have three different numbers?

Am I misunderstanding the question? If so, how my understanding will
be constructed as question?
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Re: There are three fair dice rolled alltoghether. What is the [#permalink]
stolyar wrote:
There are three fair dice rolled alltoghether. What is the probability that the gotten numbers will all not be the SAME?


210/216 , is absolutely correct .. there are only 6 possibilities where are 3 will be the same numbers out of the 216 possible so , effectively 210 for which all three will " not " be the same... and hence the answere[/img]
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Re: There are three fair dice rolled alltoghether. What is the [#permalink]
Let's spice it up a bit. If the same 3 fair dice are thrown, can anybody find what is the probability that NO TWO numbers are the same?
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Re: There are three fair dice rolled alltoghether. What is the [#permalink]
To Paul, 2 out of three dices we can select in 3 ways, 6 possibilities to select numbers for the pair and 5 for the single dice or 5x6x3=90 ways when 2 are the same. 216-90=126/216 but the option that 3 are the same is also included. If the question is no 2 AND 3 are the same then it should be 120/216.
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Re: There are three fair dice rolled alltoghether. What is the [#permalink]
Paul,
What is the right answer?
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Re: There are three fair dice rolled alltoghether. What is the [#permalink]
Just wanted to have more replies on this but BG has the right answer. Congrats



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