A hare and a jackal are running a race. Three leaps of the

Thank you for the suggestion and solutions.

Excuse me but why do you say that the speed is 6/3 = 2?
Isn't that only the ratio between the first relation and the second one?

Cheers
J

SO think about it like this

3 Leaps of the Hare =1 ft
4 Leaps of the Jackle= 1ft

for every 6 Leaps of the Hare
OR 2ft right, because 3 Leaps is 1 ft, so 6 leaps is 2ft which they showed as \(\frac{6 Leaps}{3Leaps}\)

The Jackle takes 5 Leaps
5 Leaps is 1ft and \(\frac{1}{4}\) of a foot

\(1.25*4\) and \(2*4\) = \(8:5\)

WE WANT WHOLE STEPS SO WE MULTIPLY OUR MIXED DECIMAL NUMBER INTO A WHOLE NUMBER
ITS A RATIO, SO WHAT YOU DO TO ONE SIDE YOU MUST DO TO THE OTHER

(\(1.25:2\)) \(*4\)

I really hope i was able to help

Hi Karishma , so are you implying that this question is not on GMAT pattern , maybe it is too difficult or any other reason .

Can someone explain this?
I didn't get why these lines are the same

There is nothing wrong with the question - in fact I have made a GMAT question on this pattern (with modifications to make it suitable for GMAT) too. It is hard but it uses ratios and no advanced concept. If you get such a question in GMAT, it is fair play. The problem is with the source. If the source uses CAT questions without making them GMAT appropriate, you shouldn't use the source to prepare for GMAT. There are some popular CAT question such as buses running at regular intervals, train and bird, escalator questions etc. They are all based on very simple concepts but the application is tricky. If a prep company puts those questions in its GMAT prep material, there is nothing wrong with it but they must modify them suitably. GMAT has a worldwide clientele and the clarity of the question is paramount.

Also, I would guess that a company which puts lots of CAT questions in GMAT material perhaps does not have much of a GMAT focused team and hence would not be able to give you the insights and strategies provided by companies dedicated to GMAT.

The question is not very clear - as I said before - it is a very popular CAT question and people have come to understand what it means. Actually, this is what the question means:

A hare and a jackal are running a race. The distance covered by the hare in three leaps is equal to the distance covered by the jackal in four leaps. In the time that the hare takes six leaps, the jackal takes 5 leaps. Find the ratio of their speeds.

Size wise, 3 leaps of hare = 4 leaps of jackal
3 leaph = 4 leapj
6 leaph = 8 leapj
6 leaps of hare will be equal in distance to 8 leaps of jackal.

In the time that the hare takes six leaps, the jackal takes 5 leaps.
When the hare takes 6 leaps, they are equal to 8 leaps of jackal. In the same time, the jackal takes 5 leaps.

So in the same time, the hare and the jackal take 8 and 5 leaps respectively of equal size. So the distance they will cover in the same time will be in the ratio 8:5. So their speed will be in the ratio 8:5.

let hare's leap=4 feet
let jackal's leap=3 feet
speed ratio of hare to jackal is (4)(6):(3)(5)=8:5

Responding to a pm:


"distance hare covers =3units while at same Jackle will cover 4units"

- Not correct.

"The distance covered by the hare in three leaps is equal to the distance covered by the jackal in four leaps." means

|------|------|------| 3 leaps of hare
|-----|----|----|----| 4 leaps of jackal

Distance covered is the same. Jackal has a smaller leap.

Also, I am not sure what you mean by:
"time taken similarly is 6 units by hare and thus 5 units by jackal"

Actually, the time in which the hare takes 6 leaps, the jackal takes only 5. So again hare is faster.

Check out the solution given above.

Hi,
Notations:
\(L_{h}:\) distance traveled by the Hare in 1 leap.

\(L_{j}:\) distance traveled by the Jackal in 1 leap.

Given:
Three leaps of the Hare are equal to four leaps of the jackal.

=> \(3L_{h} = 4L_{j} = k\) (say)

=> \(L_{h} = \frac{k}{3} \textrm{ and } L_{j} = \frac{k}{4}\)


For every six leaps of the Hare, the Jackal takes 5 leaps.

Distance covered by Hare in six leaps = \(6 \times \frac{k}{3} = 2k\)

Distance covered by Jackal in 5 leaps = \(5 \times \frac{k}{4} = 1.25k\)

The ratio of their speed = 2k/1.25k = 200/125 = 8:5

Thanks.

I tried to imagina a situation. the race:
3 leaps of H = 4 leaps of J
this means that leap of H is 4, and leaps of J is 3
when they run the distance it is 6*4 and 5*3
hence it is 24:15=>8:5

This is a very flawed question because it does not specify which ratio the question is asking for. Is it asking for the speed ratio of hare to Jackal (8:5) or the ratio of Jackal to hare (5:8)? Making it worse is that both solutions are in the answer choices. This is not a good quality GMAT question!

This is a very simple question.. Though it doesn't seem to be a suitable question for GMAT.

3 leaps of hare = 4 leaps of Jackal
Lets make it short, so that I don't need to write long lines all the time.
3H=4 J
1H=4/3J
6H=(4/3)*6 = 8J
Now expand it again in sentence.
6 leaps of hare = 8 leaps of Jackal

While Hare took 6 leaps, Jackal only took 5 leap.

So, Speed = 6 leap of hare/5 leap of Jackal=8 leaps of Jackal/5 leap of Jackal = 8/5

Answer B