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Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results

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michaelkalend
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Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results [#permalink] New post   23 May 2017, 00:58
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Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results in a certain pure metal. In how many days of mining will the total amount of pure metal produced at the quarry be equal to the daily amount of ore mined?

A 10
B 100
C 250
D 400
E 1,000
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C
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amanvermagmat
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Re: Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results [#permalink] New post   23 May 2017, 01:41
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Out of 2500 tons of ore, daily amount of pure metal = 0.4% of 2500
= 0.4/100 * 2500 = 10 tons

Daily pure metal is 10 tons, We have to find number of days where it will be equal to 2500 tons
2500/10 = 250. Hence C answer
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Re: Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results [#permalink] New post   22 Feb 2018, 17:28
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michaelkalend wrote:
Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results in a certain pure metal. In how many days of mining will the total amount of pure metal produced at the quarry be equal to the daily amount of ore mined?

A 10
B 100
C 250
D 400
E 1,000


Each day 2,500 x 0.4/100 = 25 x 0.4 = 10 tons of pure metal is mined.

So it will take 2500/10 = 250 days to mine 2500 tons of pure metal.

Answer: C
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stne
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Re: Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results [#permalink] New post   17 Dec 2018, 07:22
michaelkalend wrote:
Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results in a certain pure metal. In how many days of mining will the total amount of pure metal produced at the quarry be equal to the daily amount of ore mined?

A 10
B 100
C 250
D 400
E 1,000


Dear Moderator,
Found this PS question, while going through the DS section of Arithmetic , hope we can move it to the proper place, Thank you.
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Re: Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results [#permalink] New post   17 Dec 2018, 08:01
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stne wrote:
michaelkalend wrote:
Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results in a certain pure metal. In how many days of mining will the total amount of pure metal produced at the quarry be equal to the daily amount of ore mined?

A 10
B 100
C 250
D 400
E 1,000


Dear Moderator,
Found this PS question, while going through the DS section of Arithmetic , hope we can move it to the proper place, Thank you.

___________________
Moved to PS. Thank you.
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IanStewart
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Re: Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results [#permalink] New post   12 Jul 2021, 04:45
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0.4% = 4/1000 = 1/250, and if we're getting 1/250th of what we want each day, it will take 250 days.

The "2500 tons" in the question is irrelevant and there's no need to use it here.
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Re: Of the 2,500 tons of ore mined daily at a quarry, 0.4 percent results [#permalink]
12 Jul 2021, 04:45
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