NEW HERE? LEARN MORE
closeclose
Last visit was: 24 Apr 2024, 22:25 It is currently 24 Apr 2024, 22:25
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

Currently, y percent of the members on the finance committee

SORT BY:
Date
Kudos
 1   2   
Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
u2lover
Director
Director
Joined: 14 May 2006
Posts: 709
Own Kudos [?]: 783 [57]
Given Kudos: 0
Send PM
Currently, y percent of the members on the finance committee [#permalink] New post   08 Aug 2006, 12:21
5
Kudos
52
Bookmarks
00:00
A
B
C
D
E

Difficulty:

85% (hard)

Question Stats:

58% (03:05) correct 42% (02:49) wrong based on 649 sessions
Hide Show timer Statistics
Currently, y percent of the members on the finance committee are women and next month, z percent of the men on the finance committee will resign. If no other personnel changes occur, then after the resignations next month, the men who remain on the finance committee will represent what percent of the total finance committee members?


A. \(\frac{100(100 - z)(100 - y)}{100^2 - z(100 - y)}\)

B. \(\frac{(100 - z)(100 - y)}{100}\)

C. \((100 - z)(100 - y)\)

D. \(\frac{zy}{100} - z\)

E. \(\frac{z(100 - y)}{100}\)
ShowHide Answer
Official Answer
A
Most Helpful Reply
User avatar
L
KarishmaB
Tutor
Joined: 16 Oct 2010
Posts: 14817
Own Kudos [?]: 64905 [13]
Given Kudos: 426
Location: Pune, India
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   16 Jan 2014, 20:40
8
Kudos
5
Bookmarks
Expert Reply
jlgdr wrote:
Let's say that there are a total of 100 members
Let's also say that y = 50
So there are 50 men
Now z = 10 so 45 men are left
(45/95)*100 = 9/19 *100 = 900/19

Now let's plug answer choices
Target 900/19
Inputs
y=50
z=10

Only A gives the correct answer

Hope it helps
Cheers!
J :)


Yes, number plugging is the best choice here though I would take much easier numbers to reduce the time taken. Almost no calculations will be involved.

e.g. Say 50% are women i.e. y = 50 and say 100% of men will resign i.e. z = 100 so the correct option should give me 0. I see that z = 100 is not a problem because you don't have z - 100 anywhere in the denominators.
(A), (B) and (C) have z - 100 in the numerator so they will give us 0. (D) and (E) will not. So I will only worry about (A), (B) and (C).

Now say z = 50% i.e. the remaining men will be 25/75 = 1/3. Put z = 50 and y = 50 in (B) and (C) since they are simpler and you can just see what you will get without any calculations. Neither gives 33.33. Obviously, (A) will be the correct answer. You don't even need to plug in to check.

Answer (A)
User avatar
jaynayak
Director
Director
Joined: 30 Mar 2006
Posts: 896
Own Kudos [?]: 593 [5]
Given Kudos: 0
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   11 Aug 2006, 03:04
4
Kudos
1
Bookmarks
For these questions..... I find it better to take some values for y and z

for example.
Let total finance commitee members = 100
Let y = 20 and z = 5

hence men left = 80 - 4 = 76

Percent = 7600/96

Now lets plug in values in the choices.
A = 100 * 95*80/10000 - 400
= 100 * 95*80/9600
= 7600/96
General Discussion
User avatar
ps_dahiya
VP
VP
Joined: 20 Nov 2005
Posts: 1490
Own Kudos [?]: 1133 [5]
Given Kudos: 0
Concentration: Strategy, Entrepreneurship
Schools:Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
 Q50  V34
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   08 Aug 2006, 12:39
2
Kudos
3
Bookmarks
A

Current month:
Let total = 100
No. of females = y
No. of males = 100-y

Next month:
No of females = y
No of males = (100-y)*(100-z)/100
Total = y + (100-y)*(100-z)/100
= (100y + 100^2 - 100y -100z+yz)/100
= [100^2 - z(100-y)]/100

Percentage of males = [100 * (100-y)*(100-z)/100] / [100^2 - z(100-y)]/100
i.e (100)(100 – z)(100 – y)/100^2 – z(100 – y)
User avatar
Professor
Director
Director
Joined: 29 Dec 2005
Posts: 566
Own Kudos [?]: 176 [1]
Given Kudos: 0
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   08 Aug 2006, 13:28
1
Kudos
w = y
m = 100 - y
total = 100
m after z = (100 - y) - [z (100- y)/100] = (100-z)(100-y)/100
m (after z) as a % of total = [(100-z)(100-y)/100]/[{(100-y)(100-z)/100} + y] x [100]

after solviing for y and z: m (after z) as a % of total = [100 (100-z)(100-y)]/[(100^2 - z (100-y)]

its A. imo, plugging-in is best for such a tedious calculation.
User avatar
heman
Manager
Manager
Joined: 20 Mar 2006
Posts: 104
Own Kudos [?]: 10 [0]
Given Kudos: 0
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   09 Aug 2006, 17:54
ps_dahiya wrote:
A

Current month:
Let total = 100
No. of females = y
No. of males = 100-y

Next month:
No of females = y
No of males = (100-y)*(100-z)/100
Total = y + (100-y)*(100-z)/100
= (100y + 100^2 - 100y -100z+yz)/100
= [100^2 - z(100-y)]/100

Percentage of males = [100 * (100-y)*(100-z)/100] / [100^2 - z(100-y)]/100
i.e (100)(100 – z)(100 – y)/100^2 – z(100 – y)


Ps: How are you getting 100-z/100 when Q says z% of the men. Wouldnt it be (100-y)*z/100

Heman
User avatar
Path
Intern
Intern
Joined: 07 Aug 2005
Posts: 46
Own Kudos [?]: 7 [0]
Given Kudos: 0
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   09 Aug 2006, 20:41
heman wrote:
ps_dahiya wrote:
A

Current month:
Let total = 100
No. of females = y
No. of males = 100-y

Next month:
No of females = y
No of males = (100-y)*(100-z)/100
Total = y + (100-y)*(100-z)/100
= (100y + 100^2 - 100y -100z+yz)/100
= [100^2 - z(100-y)]/100

Percentage of males = [100 * (100-y)*(100-z)/100] / [100^2 - z(100-y)]/100
i.e (100)(100 – z)(100 – y)/100^2 – z(100 – y)


Ps: How are you getting 100-z/100 when Q says z% of the men. Wouldnt it be (100-y)*z/100

Heman


z pct men left, so the number of remaining men is 100-z pct of women.
User avatar
ChrisLele
Magoosh GMAT Instructor
Joined: 28 Nov 2011
Posts: 298
Own Kudos [?]: 4562 [1]
Given Kudos: 2
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   18 Apr 2012, 15:46
1
Kudos
Expert Reply
Hi, I know this is an ancient thread :-D but was just replying in response to one of Magoosh's users who had asked me to take a look.

The responses above are fine (check out ps-dahiya's). The thing with this problem is the algebraic solution is time-consuming and unwieldy. It is not that the users are missing a more elegant algebraic solution. The take away from a question such as this one - esp., if you want to answer it in under 2 minutes - is to plug in. @Jaynayak shows how to do so in his post.

Hope that helps :).
User avatar
jlgdr
VP
VP
Joined: 06 Sep 2013
Posts: 1345
Own Kudos [?]: 2391 [2]
Given Kudos: 355
Concentration: Finance
Schools: Wharton '17 (A) HBS '17 (WA$)
Send PM
GMAT ToolKit User
Re: Currently, y percent of the members on the finance committee [#permalink] New post   16 Jan 2014, 16:00
1
Kudos
1
Bookmarks
Let's say that there are a total of 100 members
Let's also say that y = 50
So there are 50 men
Now z = 10 so 45 men are left
(45/95)*100 = 9/19 *100 = 900/19

Now let's plug answer choices
Target 900/19
Inputs
y=50
z=10

Only A gives the correct answer

Hope it helps
Cheers!
J :)
User avatar
S
Raihanuddin
Manager
Manager
Joined: 11 Sep 2013
Posts: 90
Own Kudos [?]: 537 [0]
Given Kudos: 381
Concentration: Finance, Finance
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   24 Aug 2014, 12:33
Number Plug has worked very quickly.
Let Total =100, Y= 50 and Z = 10. So New no. of men = .90*50 =45, New no. of total =100-5 =95
Percent = (45/95)*100 = 900/19. Plug the y=50 and z= 10.
Remember, first plug in easy option. You will immediately find that in B, C, D and E you are not getting 19 in denominator. Ans-A
avatar
truongynhi
Intern
Intern
Joined: 05 Jun 2015
Posts: 22
Own Kudos [?]: 8 [0]
Given Kudos: 444
Location: Viet Nam
GMAT 1: 740 Q49 V41
GPA: 3.66
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   02 Mar 2016, 21:55
VeritasPrepKarishma wrote:

Now say z = 50% i.e. the remaining men will be 25/75 = 1/3. Put z = 50 and y = 50 in (B) and (C) since they are simpler and you can just see what you will get without any calculations. Neither gives 33.33. Obviously, (A) will be the correct answer. You don't even need to plug in to check.

Answer (A)


Hi Karishma,

I tried plugging numbers for option A, but somehow I cannot get 1/3.

\(\frac{{100*(100-50)*(100-50)}}{{100*100-50*(100-50)}}=\frac{{100*50*50}}{{100^2-50^2}}=\frac{{100*50*50}}{{50*150}}=\frac{5000}{150}\)

Could you please point out what is wrong with the above calculation?
Thank you very much!
Nhi
User avatar
S
Raihanuddin
Manager
Manager
Joined: 11 Sep 2013
Posts: 90
Own Kudos [?]: 537 [0]
Given Kudos: 381
Concentration: Finance, Finance
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   02 Mar 2016, 23:03
truongynhi wrote:
VeritasPrepKarishma wrote:

Now say z = 50% i.e. the remaining men will be 25/75 = 1/3. Put z = 50 and y = 50 in (B) and (C) since they are simpler and you can just see what you will get without any calculations. Neither gives 33.33. Obviously, (A) will be the correct answer. You don't even need to plug in to check.

Answer (A)


Hi Karishma,

I tried plugging numbers for option A, but somehow I cannot get 1/3.

\(\frac{{100*(100-50)*(100-50)}}{{100*100-50*(100-50)}}=\frac{{100*50*50}}{{100^2-50^2}}=\frac{{100*50*50}}{{50*150}}=\frac{5000}{150}\)

Could you please point out what is wrong with the above calculation?
Thank you very much!
Nhi


You can look at my solution

Number Plug has worked very quickly.
Let Total =100, Y= 50 and Z = 10. So New no. of men = .90*50 =45, New no. of total =100-5 =95
Percent = (45/95)*100 = 900/19. Plug the y=50 and z= 10.

Remember, first plug the numbers in easy option. You will immediately find that in B, C, D and E you are not getting 19 in the denominator. Ans-A
avatar
truongynhi
Intern
Intern
Joined: 05 Jun 2015
Posts: 22
Own Kudos [?]: 8 [0]
Given Kudos: 444
Location: Viet Nam
GMAT 1: 740 Q49 V41
GPA: 3.66
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   02 Mar 2016, 23:30
Raihanuddin wrote:
You can look at my solution

Number Plug has worked very quickly.
Let Total =100, Y= 50 and Z = 10. So New no. of men = .90*50 =45, New no. of total =100-5 =95
Percent = (45/95)*100 = 900/19. Plug the y=50 and z= 10.

Remember, first plug the numbers in easy option. You will immediately find that in B, C, D and E you are not getting 19 in the denominator. Ans-A


Hi Raihanuddin,
Thank you for the prompt reply. But you didn't address my question. I understood the plugging method and knew that B, C, D, and E are wrong. I am asking about the arithmetic operation when plugging z=y=50 into option A.
avatar
chinelj
Intern
Intern
Joined: 09 Dec 2014
Posts: 2
Own Kudos [?]: 1 [0]
Given Kudos: 15
WE:Information Technology (Health Care)
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   12 Apr 2017, 14:23
jaynayak wrote:
For these questions..... I find it better to take some values for y and z

for example.
Let total finance commitee members = 100
Let y = 20 and z = 5

hence men left = 80 - 4 = 76

Percent = 7600/96

Now lets plug in values in the choices.
A = 100 * 95*80/10000 - 400
= 100 * 95*80/9600
= 7600/96


I'm sure there is an obvious answer to this but why did you subtract by 4 and not 5
User avatar
L
KarishmaB
Tutor
Joined: 16 Oct 2010
Posts: 14817
Own Kudos [?]: 64905 [0]
Given Kudos: 426
Location: Pune, India
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   13 Apr 2017, 04:11
Expert Reply
chinelj wrote:
jaynayak wrote:
For these questions..... I find it better to take some values for y and z

for example.
Let total finance commitee members = 100
Let y = 20 and z = 5

hence men left = 80 - 4 = 76

Percent = 7600/96

Now lets plug in values in the choices.
A = 100 * 95*80/10000 - 400
= 100 * 95*80/9600
= 7600/96


I'm sure there is an obvious answer to this but why did you subtract by 4 and not 5


The question says "z percent of the men will resign."
If there are 80 men (assuming 20% are women and total employees are 100), then 5% of 80 is 4. That is why you subtract 4.
avatar
B
brandon7
Intern
Intern
Joined: 09 Mar 2017
Posts: 26
Own Kudos [?]: 14 [0]
Given Kudos: 24
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   22 Jul 2017, 08:36
Can someone help me out why I am being such an idiot here? I can calculate the denominator but I get a slightly different answer for the numerator. Obviously I am missing something here, but I can't seem to figure it out.

Let's say:

T=Total
Y=W=Women
M=Men
Z=Men resigning

The # of men left over after men have resigned=
((100-y)/100) * T *((100-z)/100). I.e. (% of Men * Total)=# of Men * (% of Men Resigning).

The denominator= Women + men who haven't signed=
y/100*T + ((100-y)/100) * T *((100-z)/100)

Thus when I reduce this I get:
1. ((T)(100-y)(100-z))/100^2)/(((100*Y*T)/100^2)+((T)(100-y)(100-z))/100^2))

2. ((T)(100-y)(100-z))/100^2) / (((100*Y*T)+((100-y)(100-z)(t)))/100^2

3. ((T)(100-y)(100-z))/100^2) * 100^2/ (t)(100^2-z(100-y))

4. (100-y)(100-z))/(100^2-z(100-y))

What am I missing? Thanks!
User avatar
L
KarishmaB
Tutor
Joined: 16 Oct 2010
Posts: 14817
Own Kudos [?]: 64905 [0]
Given Kudos: 426
Location: Pune, India
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   05 Aug 2017, 02:54
Expert Reply
brandon7 wrote:
Can someone help me out why I am being such an idiot here? I can calculate the denominator but I get a slightly different answer for the numerator. Obviously I am missing something here, but I can't seem to figure it out.

Let's say:

T=Total
Y=W=Women
M=Men
Z=Men resigning

The # of men left over after men have resigned=
((100-y)/100) * T *((100-z)/100). I.e. (% of Men * Total)=# of Men * (% of Men Resigning).

The denominator= Women + men who haven't signed=
y/100*T + ((100-y)/100) * T *((100-z)/100)

Thus when I reduce this I get:
1. ((T)(100-y)(100-z))/100^2)/(((100*Y*T)/100^2)+((T)(100-y)(100-z))/100^2))

2. ((T)(100-y)(100-z))/100^2) / (((100*Y*T)+((100-y)(100-z)(t)))/100^2

3. ((T)(100-y)(100-z))/100^2) * 100^2/ (t)(100^2-z(100-y))

4. (100-y)(100-z))/(100^2-z(100-y))

What am I missing? Thanks!


When you convert something into a percentage, you multiply by 100. Say, 2 is what percent of 4?
2/4 * 100 = 50
So 2 is 50% of 4.

I think you have missed multiplying by 100 at the end.
User avatar
L
KarishmaB
Tutor
Joined: 16 Oct 2010
Posts: 14817
Own Kudos [?]: 64905 [1]
Given Kudos: 426
Location: Pune, India
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   05 Aug 2017, 03:14
1
Kudos
Expert Reply
brandon7 wrote:
Can someone help me out why I am being such an idiot here? I can calculate the denominator but I get a slightly different answer for the numerator. Obviously I am missing something here, but I can't seem to figure it out.

Let's say:

T=Total
Y=W=Women
M=Men
Z=Men resigning

The # of men left over after men have resigned=
((100-y)/100) * T *((100-z)/100). I.e. (% of Men * Total)=# of Men * (% of Men Resigning).

The denominator= Women + men who haven't signed=
y/100*T + ((100-y)/100) * T *((100-z)/100)

Thus when I reduce this I get:
1. ((T)(100-y)(100-z))/100^2)/(((100*Y*T)/100^2)+((T)(100-y)(100-z))/100^2))

2. ((T)(100-y)(100-z))/100^2) / (((100*Y*T)+((100-y)(100-z)(t)))/100^2

3. ((T)(100-y)(100-z))/100^2) * 100^2/ (t)(100^2-z(100-y))

4. (100-y)(100-z))/(100^2-z(100-y))

What am I missing? Thanks!


When you convert something into a percentage, you multiply by 100. Say, 2 is what percent of 4?
2/4 * 100 = 50
So 2 is 50% of 4.

I think you have missed multiplying by 100 at the end.
avatar
B
pjthug
Intern
Intern
Joined: 12 Feb 2017
Posts: 5
Own Kudos [?]: 2 [0]
Given Kudos: 73
Location: United States (TX)
Schools: Booth '21 (D) Tuck '21 (D) Duke '21 (WL) Tepper '21 (A$) Stern '21 (M)
Send PM
Re: Currently, y percent of the members on the finance committee [#permalink] New post   07 Aug 2017, 18:15
Here's an easier number, how about 0? :)

If there are zero percent women, and zero percent men that leave, you know that the answer you are looking for is 100. (Since no women are part of the set, and no men leave, you should have 100 percent men).

Only A and B result in 100 when plugged in. Now use some logic to weed out answer B, let's pretend z=1 (one percent men leave) but still y=0 (no women). B would give us 99 percent men, which is false since it is still ALL men (even if some leave).

Therefore, you are left with A.
avatar
B
Shrish_nayak
Intern
Intern
Joined: 03 Apr 2017
Posts: 20
Own Kudos [?]: 3 [0]
Given Kudos: 33
Send PM
Currently, y percent of the members on the finance committee [#permalink] New post   30 Dec 2017, 05:11
VeritasPrepKarishma wrote:
jlgdr wrote:
Let's say that there are a total of 100 members
Let's also say that y = 50
So there are 50 men
Now z = 10 so 45 men are left
(45/95)*100 = 9/19 *100 = 900/19

Now let's plug answer choices
Target 900/19
Inputs
y=50
z=10

Only A gives the correct answer

Hope it helps
Cheers!
J :)


Yes, number plugging is the best choice here though I would take much easier numbers to reduce the time taken. Almost no calculations will be involved.

e.g. Say 50% are women i.e. y = 50 and say 100% of men will resign i.e. z = 100 so the correct option should give me 0. I see that z = 100 is not a problem because you don't have z - 100 anywhere in the denominators.
(A), (B) and (C) have z - 100 in the numerator so they will give us 0. (D) and (E) will not. So I will only worry about (A), (B) and (C).

Now say z = 50% i.e. the remaining men will be 25/75 = 1/3. Put z = 50 and y = 50 in (B) and (C) since they are simpler and you can just see what you will get without any calculations. Neither gives 33.33. Obviously, (A) will be the correct answer. You don't even need to plug in to check.

Answer (A)


Hello Karishma,

Unfortunately, I am not getting the correct answer. I tried the below:

total = 20 people
women = 10 men=10 z%=10

so 10*10/100=1 hence remaining men = 9

total is 9/19*100 = 900/19


A. 100(100−10)(100−10)
-------------------------- = 100*90*90/10000-900= 810000/9100 = 8100/91
100^2−10(100−10)

Can you help me where did I go wrong with this one? VeritasPrepKarishma

Best Regards,
Shrish
GMAT Club Bot
gmatclubot
Currently, y percent of the members on the finance committee [#permalink]
30 Dec 2017, 05:11
 1   2   
Moderators:
Bunuel
Math Expert
92900 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions