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Re: While working alone at their respective constant rates, Audrey took 4 [#permalink]
Bunuel wrote:
While working alone at their respective constant rates, Audrey took 4 hours to complete a certain job. Ferris can do the same job in 3 hours. Audrey and Ferris decided to collaborate on the job, working at their respective rates. While Audrey worked continuously, Ferris took 3 breaks of equal length. If the two completed the job together in 2 hours, how many minutes long was each of Ferris’ breaks ?

A. 5
B. 10
C. 15
D. 20
E. 25


rate of A = 1/4
rate of f=1/3
total work done ;
7/12 and work done in 2 hrs
7/12 * 2 ; 7/6
so work left ; 7/6-1 ; 1/6
this work left was completed in 3 parts ; so 1/6/1/3 ; 1/2 done per hr
1/2 * 60 ; 30 mins or say 10 mins each
IMO B
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Re: While working alone at their respective constant rates, Audrey took 4 [#permalink]
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Lets try to solve this verbally. Audrey will do 50% of the work in 2hrs. Rest 50% of the work will be done by Ferris. But Ferris can do 50% of the work in 1.5 hrs as per question. So if he worked 2hrs and took equal breaks, then those breaks have to be of 10min each. i.e 120 min - 30(3*10) min = 1.5 hrs.

So B.

Bunuel wrote:
While working alone at their respective constant rates, Audrey took 4 hours to complete a certain job. Ferris can do the same job in 3 hours. Audrey and Ferris decided to collaborate on the job, working at their respective rates. While Audrey worked continuously, Ferris took 3 breaks of equal length. If the two completed the job together in 2 hours, how many minutes long was each of Ferris’ breaks ?

A. 5
B. 10
C. 15
D. 20
E. 25
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Re: While working alone at their respective constant rates, Audrey took 4 [#permalink]
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In time and Work, completion of work = 1

When 2 or more people work for different time periods, then the sum of the fractions of work done by each person = 1

Work done by Audrey in 1 hour = \(\frac{1}{4}\)

Work done by Ferris in 1 hour = \(\frac{1}{3}\)



Fraction of work done by Audrey in 2 hours = \(\frac{2}{4}\) = \(\frac{1}{2}\)


Let length of Ferris's break = x hours each


Total Length of the break = 3x hours


Amount of time worked by Ferris = 2 - 3x hours


Fraction of work done by Ferris in 2 hours = \(\frac{2 - 3x}{3}\)


Therefore \(\frac{1}{2} \space + \space \frac{2 - 3x}{3} = 1\)


\(\frac{3 \space + \space 2 \space* \space(2\space - \space 3x)}{6} = 1\)


3 + 4 - 6x = 6

\(x = \frac{1}{6}\) hours = 10 minutes


Option B

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Re: While working alone at their respective constant rates, Audrey took 4 [#permalink]
Given, A = 4 hrs and F = 3 hrs.

To complete 1 work,

1/3* (2-3T) + 1/4*2 =1 or, T = 7/6 -1 = 1/6 hrs = 10 mins

So, I think B. :)
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Re: While working alone at their respective constant rates, Audrey took 4 [#permalink]
Let total manpower required for the work be 12 units. (LCM of 4,3)
Therefore, Audrey does 3 units of work each hour. (12 units/3 hours)
Similarly, Ferris does 4 units of work each hour.
According to the question, when they work together they take 2 hours to complete the work.
Audrey does 6 units(3*2) of work.
Remaining work=12-6=6 units
Ferris should have finished this amount of work in 1.5 hours (6 units/4).
But the actual time is 2 hrs.
Therefore break interval=((2*60)-(1.5*60))/3=10 minutes
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Re: While working alone at their respective constant rates, Audrey took 4 [#permalink]
A - 3 units per hour
F- 4 units per hour

Work - 12 units

A - 6 units
F - 6 units in 2 hours

He must take 1.5 hours for 6 units. So break of .5 hour or 30 minutes

Each break is of 10 min length
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Re: While working alone at their respective constant rates, Audrey took 4 [#permalink]
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