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If y and z are positive integers such that y2z=123.24, the remainder

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kiran120680
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If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   Updated on: 04 May 2019, 10:01
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If y and z are positive integers such that y/2z=123.24, the remainder obtained when y is divided by z is what percentage lesser than z?


A. 24%
B. 48%
C. 52%
D. 76%
E. Cannot be Determined
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Official Answer
C

Originally posted by kiran120680 on 04 May 2019, 08:57.
Last edited by kiran120680 on 04 May 2019, 10:01, edited 1 time in total.
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LeoN88
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Re: If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   25 May 2019, 06:25
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kiran120680 wrote:
If y and z are positive integers such that y/2z=123.24, the remainder obtained when y is divided by z is what percentage lesser than z?


A. 24%
B. 48%
C. 52%
D. 76%
E. Cannot be Determined


Good sum,

Concept
X = yQ + R
x when divided by y gives a quotient Q and remainder R such that 0<=R<y

y/z = 246.48

y= 246*z + z(.48)
Remainder= .48z

Answer= { z(1-.48)/z }*100 = 52% C
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Re: If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   04 May 2019, 09:31
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Y and x are integers so the multiplication can not be in decimal


Can you check if there is any typo ....

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Manaswini123
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Re: If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   04 May 2019, 23:28
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If y/2z = 123.24 then y/z =246.48
That implies z*0.48 is the remainder which is 0.52 times lesser of z

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kiran120680
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Re: If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   25 May 2019, 06:16
kiran120680 wrote:
If y and z are positive integers such that y/2z=123.24, the remainder obtained when y is divided by z is what percentage lesser than z?


A. 24%
B. 48%
C. 52%
D. 76%
E. Cannot be Determined


Kudos for a better explanation.
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kiran120680
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Re: If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   25 May 2019, 08:20
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LeoN88 wrote:
kiran120680 wrote:
If y and z are positive integers such that y/2z=123.24, the remainder obtained when y is divided by z is what percentage lesser than z?


A. 24%
B. 48%
C. 52%
D. 76%
E. Cannot be Determined


Good sum,

Concept
X = yQ + R
x when divided by y gives a quotient Q and remainder R such that 0<=R<y

y/z = 246.48

y= 246*z + z(.48)
Remainder= .48z

Answer= { z(1-.48)/z }*100 = 52% C


Thanks for explanation :thumbup:
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Re: If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   15 Apr 2020, 07:53
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y/2z = 123+24/100
y/2z = 12300+24/100
y/z = 12300/50 + 24/50
y/z = 12300/50 +12/25
here 12 is the R and 25 is the divisor (z)
Ques: R (12) is what % lesser than the divisor Z (25)

(25-12/25)*100 = 52

is this approach correct? chetan2u GMATinsight
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Re: If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   15 Apr 2020, 08:29
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Kritisood wrote:
y/2z = 123+24/100
y/2z = 12300+24/100
y/z = 12300/50 + 24/50
y/z = 12300/50 +12/25
here 12 is the R and 25 is the divisor (z)
Ques: R (12) is what % lesser than the divisor Z (25)

(25-12/25)*100 = 52

is this approach correct? chetan2u GMATinsight



Yes, you are correct. What you are finally doing is taking z as 25..
so y/(2*25)=123.24....y=123.24*50=6162..
so y/z=6162/25=6150/25 + 12/25... So remainder is 12 and z=25
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Re: If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   15 Apr 2020, 08:58
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Kritisood wrote:
y/2z = 123+24/100
y/2z = 12300+24/100
y/z = 12300/50 + 24/50
y/z = 12300/50 +12/25
here 12 is the R and 25 is the divisor (z)
Ques: R (12) is what % lesser than the divisor Z (25)

(25-12/25)*100 = 52

is this approach correct? chetan2u GMATinsight


That's not just fine. It's smart Kritisood

All the best! :) :thumbsup:
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If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   17 Jul 2020, 14:22
Y/2Z = 123.24

Y/Z = 244.48

Since, Remainder/Divisor = the decimal part

=> Remainder/Z = 0.48
=> Remainder/Z = 48/100
=> Remainder = 48 and Z = 100

To calculate remainder is what % lesser than Z
(100-48)/100 = 52/100

Answer: 52%
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If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   14 Jun 2021, 14:43
Why have people broken down it as 244 +0.48, why cant i write 243 (Z) + 1.48(Z)?

Bunuel
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abhimanyujain1711
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Re: If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   29 Jun 2021, 05:29
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hi guys,
just make it simple.

Y/2Z = 12324/100

Y/Z= 12324/50

now the remainder is 24.

now, 50-24 = 26

26/50*100 = 52 percent

took me 1.29 mins.
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Re: If y and z are positive integers such that y2z=123.24, the remainder [#permalink] New post   09 Apr 2024, 19:25
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