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Percentage

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lan583
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Percentage [#permalink] New post   16 Aug 2006, 17:14
Can anyone solve this please?

P is x% more in 1998 than in 1997 and and x% less in 1999 than in 1998. If P is 9% less in 1999 than in 1997, x=?



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Re: Percentage [#permalink] New post   16 Aug 2006, 17:40
Following the timeline

97: P 98: P(1+x) 99: P(1+x)(1-x)

in 99, P is 91% of P in 97

P(1+x)(1-x) = 0.91*P

(1+x)(1-x) = 0.91

1-x^2 = 0.91

x^2 = 0.09

x = Sq0.09 = .3 (30%)
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Re: Percentage [#permalink] New post   16 Aug 2006, 21:31
(1+x) * (1-x) = 0.91
x = 0.3 i.e 30%
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Re: Percentage [#permalink] New post   17 Aug 2006, 09:14
Let
1997 Value = 100
As 99 Value is 9% less from '97, value in 99 = 91

1998 Value = 100+x
1999 Value = 100+x - x(100+x)/100

91 = 100(100+x)-x(100+x)/100

9100 = (100+x)(100-x)

9100= 10000-x^2

or x^2 = 900
x=+30%



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Re: Percentage [#permalink]
17 Aug 2006, 09:14
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