What is the area of the trapezoid if PQ is parallel to RS, RS > PQ, th

What is the area of the trapezoid if PQ is parallel to RS, RS > PQ, the distance between the two parallel lines is 15, and the distance from R to the perpendicular drawn from P to RS is 10?

STATEMENT (1)--PR=\(\sqrt{325}\)

this statement gives no new information about the trapezoid
we can derive it from the question prompt
still, we don't know anything about QS (trapezoid can be scalene , isosceles we don't know)
so we cant find RS

area of trapezoid = \(\frac{(PQ+RS)*15}{2}\)

we don't know anything about RS so, we can't find the area of a trapezoid
INSUFFICIENT

STATEMENT (2)--QS=\(\sqrt{325}\)

we know that PR = \(\sqrt{325}\)
from this statement we know QS = \(\sqrt{325}\)
this proves that trapezoid is isoceles

so we can find the value of RS that is = 10+30+10 = 50

area of trapezoid = \(\frac{(PQ+RS)*15}{2}\) = \(\frac{(30+50)*15}{2}\) = 600

SUFFICIENT

B is the correct answer