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Is x > y? (1) x/2 = y - 3 (2) y > 6

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Bunuel
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Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink] New post   18 Sep 2019, 21:42
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A
B
C
D
E

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35% (medium)

Question Stats:

68% (01:28) correct 33% (01:22) wrong based on 79 sessions
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Is \(x > y\)?

(1) \(\frac{x}{2} = y-3\)

(2) \(y > 6\)
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C
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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink] New post   Updated on: 18 Sep 2019, 23:23
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Is x>y?

(1) \(\frac{x}{2}\)=y−3
x=2y-6
x and y can be any number(positive or negative) or fraction.
If y=1, x=-4, is x>y? NO

If y=-2, x=-10, is x>y? NO

If y=8, x=10, is x>y? YES

Different answers possible. INSUFFICIENT!

(2) y>6
If y>6, then x could be anything. Different answers possible. INSUFFICIENT!

(1) + (2)
x=2y-6 and y>6

If y=8, x=10, is x>y? YES

If y=\(\frac{21}{2}\), x=15, is x>y? YES

If y=100, x=194, is x>y? YES

Twice the y less 6 would make x ALWAYS greater.
SUFFICIENT!

If y>6(any positive number or fraction greater than 6), x would always be greater and positive. Therefore answer is option C.

Posted from my mobile device

Originally posted by EncounterGMAT on 18 Sep 2019, 21:53.
Last edited by EncounterGMAT on 18 Sep 2019, 23:23, edited 1 time in total.
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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink] New post   18 Sep 2019, 22:19
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A alone says nothing. For example for Y=4, X is 2(less than y) and for Y=8, X is 10(greater than y).

B alone says nothing as well.

Together they represent a set of points for which x>y

Hence c

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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink] New post   18 Sep 2019, 22:54
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statement 1: x/2 = y-3 meaning x=2y-6. This is insufficient because y can take infinite values some which will be less than x while other possible values of y can be greater than x.

Statement 2: y>6. Clearly insufficient because no information is provided to enable us determine x.

1+2: sufficient because combining both statements means that all possible values of x will be greater than 6, hence we can conclusively stay that x>y.

The answer is C.
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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink] New post   18 Sep 2019, 23:47
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Is x > y ?

STATEMENT (1) - \(\frac{x}{2}\) = y-3

y = \(\frac{x+6}{2}\)
if x = 8 then y = 7---is x>y?---YES
if x = 5 then y = 5.5---is x>y?---NO

STATEMENT (2) - y>6
no information is given about x
so, INSUFFICIENT

combining both statements

x = 2y-6 and y>6

if y = 6.1 then x = 6.2 ---x>y
any value of y > 6 will yield value of x that will be > y

hence, Is x>y -- the answer is YES
SUFFICIENT

C is the correct answer
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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink] New post   19 Sep 2019, 00:20
Is x > y?

(1) \(\frac{x}{2} = y − 3\)
x = 0 → y = 3, x > y NO
x = 10 → y = 8, x > y YES
INSUFFICIENT.

(2) y > 6
No information about x.
INSUFFICIENT.

Together 1) and 2)
y = 6.1 → x = 6.2, x > y YES
y = 10 → x = 14, x > y YES

SUFFICIENT.

Answer (C).
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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink] New post   19 Sep 2019, 04:32
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Quote:
Is x>y?

(1) x/2=y−3
(2) y>6


(1) x/2=y-3…x-2y=-6…x=-6+2y; substitute, \(x>y…-6+2y>y…y>6\)? insufic.
(2) y>6: no info about \(x\), insufic.
(1&2) y>6, true, sufic.

Answer (C)
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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink]
19 Sep 2019, 04:32
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