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Raffle tickets numbered consecutively from 151 through 352 are placed

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Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink] New post  14 Oct 2019, 03:33
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Raffle tickets numbered consecutively from 151 through 352 are placed in a box. What are the chances that a ticket selected at random will have a number with a tens digit of 7?

A. 2/7
B. 3/15
C. 10/101
D. 20/201
E. 21/201
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Bunuel
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Re: Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink] New post  14 Oct 2019, 03:41
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dcummins wrote:
Raffle tickets numbered consecutively from 151 through 352 are placed in a box. What are the chances that a ticket selected at random will have a number with a tens digit of 7?

A. 2/7
B. 3/15
C. 10/101
D. 20/201
E. 21/201


Similar questions to practice:
https://gmatclub.com/forum/raffle-ticke ... 36563.html (OG)
https://gmatclub.com/forum/lottery-tick ... 69315.html (e-GMAT)
https://gmatclub.com/forum/raffle-ticke ... 24260.html (MGMAT)
https://gmatclub.com/forum/a-bowl-conta ... 50544.html (Princeton Review)
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Re: Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink] New post  14 Oct 2019, 06:05
dcummins wrote:
Raffle tickets numbered consecutively from 151 through 352 are placed in a box. What are the chances that a ticket selected at random will have a number with a tens digit of 7?

A. 2/7
B. 3/15
C. 10/101
D. 20/201
E. 21/201


Total number of digits with 7 in ten's digit from 151 through 352 = {157, 167, 177, . . . . . . . . . 347} = 20
Total digits = 352 - 151 + 1 = 202

Probability = 20/202 = 10/101

IMO Option C
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Re: Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink] New post  14 Oct 2019, 09:17
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dcummins wrote:
Raffle tickets numbered consecutively from 151 through 352 are placed in a box. What are the chances that a ticket selected at random will have a number with a tens digit of 7?

A. 2/7
B. 3/15
C. 10/101
D. 20/201
E. 21/201


integers from 151 to 299 with 7 as tens place ; 2*1*10 ; 20
and from 300 to 352 7 as tens place =0 so total 20
total tickets ; 352-151+1 ; 202
P ; 20/202 ; 10/101
IMO C
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Re: Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink] New post  15 Oct 2019, 03:48
7 is in the ones digit not tens

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dcummins
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Re: Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink] New post  15 Oct 2019, 05:10
Arindamad wrote:
7 is in the ones digit not tens

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The question asks for 7 in the 10s digit’s place. So x7x
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Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink] New post  Updated on: 10 Apr 2020, 07:41
Dillesh4096 wrote:
dcummins wrote:
Raffle tickets numbered consecutively from 151 through 352 are placed in a box. What are the chances that a ticket selected at random will have a number with a tens digit of 7?

A. 2/7
B. 3/15
C. 10/101
D. 20/201
E. 21/201


Total number of digits with 7 in ten's digit from 151 through 352 = {157, 167, 177, . . . . . . . . . 347} = 20
Total digits = 352 - 151 + 1 = 202

Probability = 20/202 = 10/101

IMO Option C

Dillesh4096 wrote:
dcummins wrote:
Raffle tickets numbered consecutively from 151 through 352 are placed in a box. What are the chances that a ticket selected at random will have a number with a tens digit of 7?

A. 2/7
B. 3/15
C. 10/101
D. 20/201
E. 21/201


Total number of digits with 7 in ten's digit from 151 through 352 = {157, 167, 177, . . . . . . . . . 347} = 20
Total digits = 352 - 151 + 1 = 202

Probability = 20/202 = 10/101

IMO Option C

Hi Dillesh4096
question says: 7 in the tens digit (not unit digit). So, they should be 170,171,172,....up to 179 (total 10 digits) and 270,271,272,...... up to 279 (total 10 digits).
Probability \(\frac{20}{202}\)-->\(\frac{10}{101}\)
The answer is C
Isn't it buddy?
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Originally posted by TheUltimateWinner on 08 Apr 2020, 17:00.
Last edited by TheUltimateWinner on 10 Apr 2020, 07:41, edited 1 time in total.
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Re: Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink] New post  10 Apr 2020, 07:24
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dcummins wrote:
Raffle tickets numbered consecutively from 151 through 352 are placed in a box. What are the chances that a ticket selected at random will have a number with a tens digit of 7?

A. 2/7
B. 3/15
C. 10/101
D. 20/201
E. 21/201


In the 100s, there are 10 numbers with tens digit of 7: 170, 171, …, 179.

In the 200s, there are also 10 numbers with tens digit of 7: 270, 271, …, 279.

In the 300s, there are no numbers with tens digit of 7 that are less than or equal to 352.

Since there are a total of 352 - 151 + 1 = 202 numbers and 20 of them have tens digit of 7, the probability is 20/202 = 10/101.

Answer: C
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Re: Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink] New post  22 Nov 2020, 14:17
dcummins wrote:
Raffle tickets numbered consecutively from 151 through 352 are placed in a box. What are the chances that a ticket selected at random will have a number with a tens digit of 7?

A. 2/7
B. 3/15
C. 10/101
D. 20/201
E. 21/201


352 - 151 = 201
201 + 1 (to include the number 352) = 202

Numbers with a tens digit of 7=
170, 171, 172,...,179 = 10 numbers
270, 271, 272,...279 = 10 numbers

total = 20 numbers with a tens digit of 7

20/202 = 10/101

Answer is C.
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Re: Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink] New post  27 Mar 2024, 22:19
No need to solve I guess.

Total number of cards are 202 so that goes into the denominator. Out of all options only C has a denominator that’s a factor of 202. So only C could be the answer.


Let me know if this reasoning is right?
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Re: Raffle tickets numbered consecutively from 151 through 352 are placed [#permalink]
27 Mar 2024, 22:19
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