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Angelina walked 360 meters from her home to the grocery at a constant

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Bunuel
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Angelina walked 360 meters from her home to the grocery at a constant [#permalink] New post   06 Nov 2019, 06:26
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Angelina walked 360 meters from her home to the grocery at a constant speed. She then walked 480 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym?

A. 2
B. 3
C. 4
D. 6
E. 12


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anniejay
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Re: Angelina walked 360 meters from her home to the grocery at a constant [#permalink] New post   06 Nov 2019, 06:39
R(t+40)=360 .... eq. 1
2Rt=480.... eq 2
Rt=240... eq 3

Substitute 3 in 1
R=3
Rate from grocery to gym is twice home to grocery
Hence; 2R= 6

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Re: Angelina walked 360 meters from her home to the grocery at a constant [#permalink] New post   06 Nov 2019, 07:01
Bunuel wrote:
Angelina walked 360 meters from her home to the grocery at a constant speed. She then walked 480 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym?

A. 2
B. 3
C. 4
D. 6
E. 12


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\(D (Grocery-Gym)/ D (Home-Gym)=480/360=4/3\)
\(4/3=Speed (Grocery-Gym) * Time(Grocery-Gym)/Speed(Home-Gym)* Time(Home-Gym)\)
\(4/3=2*(t-40)/t\)
t=120
t-40=80
Speed (Grocery-Gym)=\(480/80\)
=6
D:)
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Re: Angelina walked 360 meters from her home to the grocery at a constant [#permalink] New post   19 Nov 2019, 02:53
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Let us assume the speed as V from home to grocery. => Speed 2V from Grocery to Gym.
Let us assume the time from Home to Grocery as T. => Time T-40 from Grocery to Gym.

=> V= 360/t & 2V = 480/(t-40)

Solving we get T=120.

=> 2V = 6.

Ans D
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Re: Angelina walked 360 meters from her home to the grocery at a constant [#permalink] New post   22 Nov 2019, 13:05
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Bunuel wrote:
Angelina walked 360 meters from her home to the grocery at a constant speed. She then walked 480 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym?

A. 2
B. 3
C. 4
D. 6
E. 12


Are You Up For the Challenge: 700 Level Questions



Letting r = Angelina’s normal speed, we can create the equation for the time:

360/r = 480/(2r) + 40

360/r = 240/r + 40

120/r = 40

120 = 40r

3 = r

Since her speed from the grocery to the gym was 2r, her speed was 6 m/sec..

Answer: D
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Re: Angelina walked 360 meters from her home to the grocery at a constant [#permalink] New post   16 Jun 2021, 06:23
[360][/T1]= 240/T1-40 = t1= 120 , 2s= 480/80 = 6 IMO D
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Re: Angelina walked 360 meters from her home to the grocery at a constant [#permalink] New post   17 Feb 2023, 05:21
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Re: Angelina walked 360 meters from her home to the grocery at a constant [#permalink]
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