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(60! − 59!)/58! =

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Bunuel
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(60! − 59!)/58! = [#permalink] New post   16 Dec 2019, 00:50
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\(\frac{60! − 59!}{58!} =\)

A. 59*58
B. 60*59
C. 58^2
D. 59^2
E. 60^2
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D
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Re: (60! − 59!)/58! = [#permalink] New post   16 Dec 2019, 00:55
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Bunuel wrote:
\(\frac{60! − 59!}{58!} =\)

A. 59*58
B. 60*59
C. 58^2
D. 59^2
E. 60^2


\(\frac{60! − 59!}{58!} =\frac{60*59*58!-59*58!}{58!}=\frac{58!(60*59-59)}{58!}=59(60-1)=59^2\)

D
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Re: (60! − 59!)/58! = [#permalink] New post   16 Dec 2019, 01:02
\(\frac{60! − 59!}{58!} =\)

Taking Common 58! - \(\frac{58![60*59 - 59]}{58!}\)

Cancelling 58! and taking 59 common - \(59[60 - 1]\)
Solving - 59*59 - \(59^2 \)
Option 'D'
Bunuel wrote:
\(\frac{60! − 59!}{58!} =\)

A. 59*58
B. 60*59
C. 58^2
D. 59^2
E. 60^2
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Re: (60! − 59!)/58! = [#permalink] New post   16 Dec 2019, 14:24
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= \(\frac{60!}{58!} - \frac{59!}{58!} = 60*59 - 59 = (60 - 1) * 59 = 59^2\)

Ans: D


Bunuel wrote:
\(\frac{60! − 59!}{58!} =\)

A. 59*58
B. 60*59
C. 58^2
D. 59^2
E. 60^2
GMAT Club Bot
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Re: (60! − 59!)/58! = [#permalink]
16 Dec 2019, 14:24
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