Last visit was: 23 Apr 2024, 12:16 It is currently 23 Apr 2024, 12:16

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
Manager
Manager
Joined: 13 Aug 2018
Posts: 59
Own Kudos [?]: 398 [5]
Given Kudos: 523
Send PM
Tutor
Joined: 26 Jun 2014
Status:Mentor & Coach | GMAT Q51 | CAT 99.98
Posts: 452
Own Kudos [?]: 759 [4]
Given Kudos: 8
Send PM
Intern
Intern
Joined: 16 May 2023
Posts: 13
Own Kudos [?]: 2 [0]
Given Kudos: 3
Send PM
Math Expert
Joined: 02 Sep 2009
Posts: 92881
Own Kudos [?]: 618575 [0]
Given Kudos: 81562
Send PM
Re: What is the summation of the all 2-digit numbers that are divided by 3 [#permalink]
Expert Reply
Yeetyeti38 wrote:
sujoykrdatta wrote:
Question:
What is the summation of all the 2-digit numbers that are divisible by 3?

Solution:
The first 2 digit number is 12 = 3 * 4
The first 2 digit number is 99 = 3 * 33

The number of such terms = 33-4+1 = 30

Thus, required sum

= 3*4 + 3*5 + ... 3*33
= 3(4 + 5 + ... 33)

Since the numbers 4,5,6... Have a constant difference between consecutive terms (i.e. are in Arithmetic Progression), the sum can be calculated as:

Sum of 4,5,6,...33
= Mean * Number of terms
= [(1st term + Last term)/2] * (Number of terms)

= [(4+33)/2] * 30
= 37*15 = (37*3)*5
= 111*5 = 555

Thus, the required sum

= 3(4 + 5 + ... 33)
= 3 * 555
= 1665

Answer B


Note: The answer options aren't so well thought of. First, they should be in ascending order.
Next, it's too easy to decide the answer by looking at the options - only 111 and 1665 are multiples of 3; of which 111 is just too small.
Third, what is 0 doing as an option here!!!


Posted from my mobile device

­I don't understand why 0 is wrong...the question asks for all 2-digit numbers divisible by three, not all positive 2-digit numbers divisible by three. If we include the negative numbers into the summation, it would be 0.

Why shouldn't we include negative numbers?

­
Yes, the question should ask about positive integers. Not a good wording. So, ingonre and move on.
GMAT Club Bot
Re: What is the summation of the all 2-digit numbers that are divided by 3 [#permalink]
Moderators:
Math Expert
92881 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne