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Math Expert
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Re: Is x < y? (1) xz < yz (2) –3x > 6y [#permalink]
Expert Reply
Bunuel wrote:
Is x < y?

(1) xz < yz
(2) –3x > 6y


Solution:
Statement 1:\( xz < yz\)
    • If\( z = 1,\) then
      o \(x < y\)
    • If \(z = -1\), then
      o \(-x < -y => x > y\)
We are getting two different results.
Hence, statement 1 is not sufficient. We can eliminate answer options A and D.
Statement 2:\( -3x > 6y\)
    • If \(x = - 5\) and\( y= 1,\) then
      o \(-3*-5 > 6*1 \) and \( x < y\)
    • If\( x = 1 \) and \( y = -1,\) then
      o \(-3*1 > -6\) and \( x > y\)
We are again getting two different results.
Hence, statement 2 is also not sufficient. We can eliminate answer option B.
Combining both the statements:
From statement 1: x<y or x > y
From statement 2: x<y or y>y
Even after combining the two, we won't be able to figure out if x is greater or lesser than y.
Hence, the correct answer is Option E.
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Re: Is x < y? (1) xz < yz (2) 3x > 6y [#permalink]
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Re: Is x < y? (1) xz < yz (2) 3x > 6y [#permalink]
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