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A mixture of 240 liters contains milk and water in the ratio of 5 : 3.

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TheNightKing
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A mixture of 240 liters contains milk and water in the ratio of 5 : 3. [#permalink] New post   27 Mar 2020, 04:14
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A mixture of 240 liters contains milk and water in the ratio of 5 : 3. A milkman mixes some more water in it and claim to sell it at cost price. If cost price of pure milk is Rs. 20/liter and water is freely available and milkman made a total profit of 80% on cost price of pure milk then find amount of water he mixed in the milk.
(a) 20 liters
(b) 30 liters
(c) 35 liters
(d) 40 liters
(e) 45 liters
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A mixture of 240 liters contains milk and water in the ratio of 5 : 3. [#permalink] New post   28 Mar 2020, 21:37
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TheNightKing wrote:
A mixture of 240 liters contains milk and water in the ratio of 5 : 3. A milkman mixes some more water in it and claim to sell it at cost price. If cost price of pure milk is Rs. 20/liter and water is freely available and milkman made a total profit of 80% on cost price of pure milk then find amount of water he mixed in the milk.
(a) 20 liters
(b) 30 liters
(c) 35 liters
(d) 40 liters
(e) 45 liters


In the 240 liters , pure milk is 150 liters and water is 90 Liters since ratio is 5:3

Let \(x\) be the liters of water added then

\(20(240+x)= \frac{180}{100}*150*20\)
\(x=30\)

Ans-B
Hope it's clear.
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Re: A mixture of 240 liters contains milk and water in the ratio of 5 : 3. [#permalink] New post   31 Mar 2020, 05:19
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TheNightKing wrote:
A mixture of 240 liters contains milk and water in the ratio of 5 : 3. A milkman mixes some more water in it and claim to sell it at cost price. If cost price of pure milk is Rs. 20/liter and water is freely available and milkman made a total profit of 80% on cost price of pure milk then find amount of water he mixed in the milk.
(a) 20 liters
(b) 30 liters
(c) 35 liters
(d) 40 liters
(e) 45 liters


Please explain this again
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Re: A mixture of 240 liters contains milk and water in the ratio of 5 : 3. [#permalink] New post   31 Mar 2020, 11:59
akritigpi46 wrote:
TheNightKing wrote:
A mixture of 240 liters contains milk and water in the ratio of 5 : 3. A milkman mixes some more water in it and claim to sell it at cost price. If cost price of pure milk is Rs. 20/liter and water is freely available and milkman made a total profit of 80% on cost price of pure milk then find amount of water he mixed in the milk.
(a) 20 liters
(b) 30 liters
(c) 35 liters
(d) 40 liters
(e) 45 liters


Please explain this again


Hi akritigpi46,

Specifically what didn't you understand? You need to ask specifically, for example did you not understand how I got 150 and 90 or did you not understand why I took \(20(240+x)\).
If you be a little more specific, perhaps I can explain better.

Hope you understand, thanks.
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Re: A mixture of 240 liters contains milk and water in the ratio of 5 : 3. [#permalink] New post   05 Aug 2020, 07:31
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240L of the mixture contains Milk and Water in the ratio 5:3

We have Selling price of the mixture (as per the milkman) = Actual profit made on pure milk

(1) Let x Liters of water be added

Then Total Mixture = 240 + x Liters

He professes to sell this mixture at cost price, i.e at Rs 20.

Therefore the Selling price (as per milkman) = (240 + x) * 20 = 4800 + 20x


(2) Amount of Milk = \(\frac{5}{8}\) * 240 = 150L

He sells the 150L at 80% profit on the Cost price.

80% profit on Rs 20 = 20 * \(\frac{180}{100}\) = Rs 36

Selling Price of 150L of pure milk = 36 * 150 = Rs 5400


Equating (1) and (2)

4800 + 20x = 5400

20x = 600

x = 30L

Option B

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Re: A mixture of 240 liters contains milk and water in the ratio of 5 : 3. [#permalink] New post   27 Dec 2023, 04:30
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Re: A mixture of 240 liters contains milk and water in the ratio of 5 : 3. [#permalink]
27 Dec 2023, 04:30
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