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If (90x)^(1/3) and (y/75)^(1/2) are positive integers, and both x and [#permalink]
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Bunuel wrote:
If \(\sqrt[3]{90x}\) and \(\sqrt{\frac{y}{75}}\) are positive integers, and both x and y are integers, what is the least possible value of \(xy\) ?

A. 20500
B. 21500
C. 22500
D. 23500
E. 24500


\(\sqrt[3]{90x}\) is an Integer i.e. 90x must be a PERFECT CUBE

CONCEPT: For a number to be a perfect cube, all prime factors must have exponents which are multiples of 3


i.e. \(90x = 2*3^2*5*x\)

ie.. x must be minimum \(2^2*3*5^2\)



\(\sqrt{\frac{y}{75}}\) is an Integer i.e. \(\frac{y}{75}\) must be a PERFECT SQUARE

CONCEPT: For a number to be a perfect square, all prime factors must have exponents which are multiples of 2


i.e. \(\frac{y}{75} = 1\)

ie.. y must be minimum \(75\)


\(x*y_{min} = 2^2*3*5^2*75 = 22500\)



Answer: Option C
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Re: If (90x)^(1/3) and (y/75)^(1/2) are positive integers, and both x and [#permalink]
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Re: If (90x)^(1/3) and (y/75)^(1/2) are positive integers, and both x and [#permalink]
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