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M is the set of positive and negative integers that are multiples of 5

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Bunuel
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M is the set of positive and negative integers that are multiples of 5 [#permalink] New post   10 Jul 2020, 04:36
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M is the set of positive and negative integers that are multiples of 5. M = ( ...... -15. -10. -5. 0. 5. 10. 15 ...... ). Integers A and B are members of set M. Which of the following expression is NOT a member of set M?

A. AB
B. A/B
C. A + B
D. A^2 + B^2
E. A - B
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B
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rahulsinha2103
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Re: M is the set of positive and negative integers that are multiples of 5 [#permalink] New post   10 Jul 2020, 04:43
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(B) . Assuming the integers are A and B(not 8).

Solved by quickly putting some values for A and B. Consider A = 5 and B = 15. A/B = 5/15 = 1/3 = 0.33, which is not an integer. Therefore, expression A/B doesn't belong to set M.
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Re: M is the set of positive and negative integers that are multiples of 5 [#permalink] New post   10 Jul 2020, 04:44
Let A is 5X and B be 5Y

Putting value in options

A. AB = 5x*5y = 25xy (Part of set M)

B. A/B = 5x/5y = X/Y (can or can't be a part of set M)

C. A + B = 5x+5y = 5(x+y) (part of set M)

D. A^2 + B^2 = 25x^2 + 25y^2 (part of set M)

E. A - B = 5X-5Y = 5(x-y) (part of set M)

Answer is B

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Re: M is the set of positive and negative integers that are multiples of 5 [#permalink] New post   10 Jul 2020, 04:45
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rahulsinha2103 wrote:
(B) . Assuming the integers are A and B(not 8).

Solved by quickly putting some values for A and B. Consider A = 5 and B = 15. A/B = 5/15 = 1/3 = 0.33, which is not an integer. Therefore, expression A/B doesn't belong to set M.

________________________
Fixed. Thank you.
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M is the set of positive and negative integers that are multiples of 5 [#permalink] New post   10 Jul 2020, 04:46
Bunuel wrote:
M is the set of positive and negative integers that are multiples of 5. M = ( ...... -15. -10. -5. 0. 5. 10. 15 ...... ). Integers A and 8 are members of set M. Which of the following expression is NOT a member of set M?

A. AB
B. A/B
C. A + B
D. A^2 + B^2
E. A - B


Let me answer this using the Substitution method:

Let A be 5 and B be -10

A. AB =5*-10 = -50 will come in the series
B. A/B =5/-10 = -0.5 will not come in the series
C. A + B =5+-10 = -5 will come in the series
D. A^2 + B^2 = 5^2+(-10)^2 = 125 will come in the series
E. A - B =5-(-10) = 15 will come in the series

Hence, OA: B
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M is the set of positive and negative integers that are multiples of 5 [#permalink]
10 Jul 2020, 04:46
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