Last visit was: 25 Apr 2024, 07:08 It is currently 25 Apr 2024, 07:08

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Senior Manager
Senior Manager
Joined: 11 Sep 2006
Posts: 456
Own Kudos [?]: 49 [0]
Given Kudos: 0
Send PM
Retired Moderator
Joined: 05 Jul 2006
Posts: 849
Own Kudos [?]: 1562 [0]
Given Kudos: 49
Send PM
Retired Moderator
Joined: 05 Jul 2006
Posts: 849
Own Kudos [?]: 1562 [0]
Given Kudos: 49
Send PM
User avatar
Senior Manager
Senior Manager
Joined: 11 Sep 2006
Posts: 456
Own Kudos [?]: 49 [0]
Given Kudos: 0
Send PM
Re: pounds of coffee [#permalink]
Yezz - I actually wrote down the question exactly as presented in the text I had...the answers were given as 3 pounds at $1.20 and 8 pounds at $1.80 - what I'm wondering is if there is an easier way than to combine equations? That's where I got bogged down...
User avatar
VP
VP
Joined: 01 May 2006
Posts: 1033
Own Kudos [?]: 251 [0]
Given Kudos: 0
Send PM
Re: pounds of coffee [#permalink]
uphillclimb wrote:
Yezz - I actually wrote down the question exactly as presented in the text I had...the answers were given as 3 pounds at $1.20 and 8 pounds at $1.80 - what I'm wondering is if there is an easier way than to combine equations? That's where I got bogged down...


To me, there is no other way than to combine the equations :)... And I could be more or less easy depending on the way to do so ;)
User avatar
Manager
Manager
Joined: 01 Feb 2006
Posts: 61
Own Kudos [?]: 6 [0]
Given Kudos: 0
Location: New York
Send PM
Re: pounds of coffee [#permalink]
Does "Valued at $18.00" mean 18(x+y) or ONLY 18. The question doesn't mention 18 per pound of mixture, does it?
User avatar
Senior Manager
Senior Manager
Joined: 11 Sep 2006
Posts: 456
Own Kudos [?]: 49 [0]
Given Kudos: 0
Send PM
Re: pounds of coffee [#permalink]
Nope. Not per pound - the $18.00 refers to the cost of the total mixture.
User avatar
Manager
Manager
Joined: 14 Aug 2006
Posts: 227
Own Kudos [?]: 201 [0]
Given Kudos: 0
Send PM
Re: pounds of coffee [#permalink]
1.20x + 1.80 y = 18.00
Increased by .30

1.50x + 2.10y = 21.30

These are the two eqs.

2x + 3y = 30
5x + 7y = 71

=>

10x + 15y = 150
10x + 14y = 142
y = 8; x = 3;
User avatar
Intern
Intern
Joined: 01 Oct 2006
Posts: 5
Own Kudos [?]: 1 [0]
Given Kudos: 0
Send PM
Re: pounds of coffee [#permalink]
This is how I solved it:

1.2x + 1.8y = 18
1.5x + 2.1y = 21.3

subtract the first equation from the second equation, you get
.3x + .3y = 3.3 or x + y = 11

substitute the above value back to either one equation and solve for x:
1.2x + 1.8 (11 - x) = 18
1.2x + 19.8 - 1.8x = 18
.6x = 1.8
x = 3
y = 11 - 3 = 8



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
GMAT Club Bot
Re: pounds of coffee [#permalink]
Moderators:
Math Expert
92912 posts
Senior Moderator - Masters Forum
3137 posts
GMAT Tutor
1905 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne