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Re: By weight, liquid A makes up 8 percent of solution R and 18 percent of [#permalink]
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total solution = 3+7 =10
total weight of A = 3*8% + 7* 18% = 1.5
% of solution A = 1.5/10 *100 = 15%
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By weight, liquid A makes up 8 percent of solution R and 18 percent of [#permalink]
\(\frac{(3×8 + 7×18)}{(3 + 7)}\) = \(\frac{150}{10}\) = 15 (C)
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Re: By weight, liquid A makes up 8 percent of solution R and 18 percent of [#permalink]
Since the question asks for the weight of the Liquid A, we should find the availability of Liquid A in the mixture. Logically the percentage does not change even when the gram raises.
8% of Liquid A in the 3 gram of R = 0.08*3=0.24
18% of Liquid A in the 7 gram of S = 0.18*7=1.62
Now we should turn this into part/total form.
1.5/10*100=15%
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Re: By weight, liquid A makes up 8 percent of solution R and 18 percent of [#permalink]
Expert Reply
Bunuel wrote:
By weight, liquid A makes up 8 percent of solution R and 18 percent of solution S. If 3 grams of solution R are mixed with 7 grams of solution S, then liquid A accounts for what percent of the weight of the resulting solution?

A. 10%
B. 13%
C. 15%
D. 19%
E. 26%


Solution:

[3(0.08) + 7(0.18)] / (3 + 7)

= [0.24 + 1.26] / 10

= 1.5/10

= 15/100

= 15%

Answer: C
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Re: By weight, liquid A makes up 8 percent of solution R and 18 percent of [#permalink]
Liq. A - 8% of 3grams (Sol. R)
Liq. A - 18% of 7 grams (Sol. S)

Total weight of both Solutions: 3+7= 10

A conc.= (8*3)+(18*7)/ (3+7) = 15
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Re: By weight, liquid A makes up 8 percent of solution R and 18 percent of [#permalink]
Liquid = x

8% of A and 18% of B
8/100 * 3gram + 18/100 * 7gram = 0.08*3+0.18*7 = 0.24+1.26 = 1.50grams

1.50 grams/total weight (7+3) = 1.50/10*100 = 15%
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Re: By weight, liquid A makes up 8 percent of solution R and 18 percent of [#permalink]
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