snorkeler wrote:
The King Edward College team won 25% of its first games and went on to win all of its remaining games. What was the ratio of games won to the games lost by the team, if there were no ties?
(1)If team had won 25% of all its games, it would have lost 30 more games than it actually did.
(2)The team won 75% of all its games.
Responding to a pm:
I would use weighted averages concept here:
There are two groups: first games and rest of the games
First games - team won 25% of these
Rest games - team won 100% of these
First look at statement 2:
Stmnt 2: We know the average "won" percentage. So we can find the ratio of number of first games to number of rest of the games and hence the ratio of games won to games lost. You don't need to do those calculations but if you want to see them, here goes:
wF/wR = (100 - 75)/(75 - 25) = 1/2
First games : Rest games = 1:2 = 4:8 (for convenience - to calculate 25%, 75% etc)
The team won 25% of first games so 1 game and 100% of rest games so 8 games. In all, the team won 9 games and lost 3.
Ratio of won:lost = 3:1
Sufficient
Stmnt 1:
The team won 25% of its first games. If it had won 25% of all games, then it would have won 25% of rest of the games too. In that case, it would have lost 75% of the rest of the games extra which is given to be 30.
75% of Rest Games = 30
Rest of the games = 40
Now we still don't know how many games were there in the first lot.
Say there were 40 games in the first lot too.
Games won = 10 + 40 = 50
Games lost = 30
Ratio of won:lost = 5:3
Say there were 100 games in the first lost.
Games won = 25 + 40 = 65
Games lost = 75
Ratio of won:lost = 13:14
Not sufficient
Answer (B)